What equipment is generally used to make lyophilized medications suitable for administering to the patient? a) Test tubes or sterile ampules O b) Petri dishes and sterile droppers c) Sterile syringes or graduated cylinders d) Measuring cups and clean, warm water
Answer:
C).
Step-by-step explanation:
-3x+2 and[(-)(x^2+5x)
3x+2 and (-x^2+5x)
3x+2-x^2+5x
-x^2-8x+2
Hope this Helps :)
It’s 10. This is because 27/3 is 9 so the ratio is by 9
Answer:
The answer to your question is 23.42 ft
Step-by-step explanation:
Data
base = 6 ft
height = 4 ft
Process
1.- Calculate the length of the rectangle. Only consider the base and the left and right sides.
Length = 6 + 4 + 4
Length = 14 ft
2.- Calculate the Perimeter of the semicircle
Formula
Perimeter = 2πr/2 = πr
-Calculate the radius
radius = 6/2 = 3 ft
-Find the perimeter
Perimeter = 2(3.14)(3)/2
-Result
Perimeter = 9.42 ft
3.- Calculate the perimeter of the window
Perimeter = 14 + 9.42
= 23.42 ft
Problem One
Call the radius of the second can = r
Call the height of the second can = h
Then the radius of the first can = 1/3 r
The height of the first can = 3*h
A1 / A2 = (2*pi*(1/3r)*(3h)] / [2*pi * r * h]
Here's what will cancel. The twos on the right will cancel. The 3 and 1/3 will multiply to one. The 2 r's will cancel. The h's will cancel. Finally, the pis will cancel
Result A1 / A2 = 1/1
The labels will be shaped differently, but they will occupy the same area.
Problem Two
It seems like the writer of the problem put some lids on the new solid that were not implied by the question.
If I understand the problem correctly, looking at it from the top you are sweeping out a circle for the lid on top and bottom, plus the center core of the cylinder.
One lid would be pi r^2 = pi w^2 and so 2 of them would be 2 pi w^2
The region between the lids would be 2 pi r h for the surface area which is 2pi w h
Put the 2 regions together and you get
Area = 2 pi w^2 + 2 pi w h
Answer: Upper left corner <<<<< Answer
