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Law Incorporation [45]
3 years ago
7

How can i do this? I need do this

Mathematics
1 answer:
Wittaler [7]3 years ago
7 0

It's a little hard to read, but I think I can help you.

a) (2^9*2^11*2^3)/(2^7)^3

(2^(9+11+3))/(2^(7*3)) Remember (a^b)^c=a^(b*c) and a^b*a^c=a^(b+c)

2^23/2^21

2^(23-21) <- Exponents with the same base when divided get subtracted

2^2

4 is the answer

b) ((0.4^2)^10)/(0.4^9*0.4^7*0.4)

0.4^(2*10)/0.4^(9+7+1)

0.4^20/0.4^17

0.4^3

0.064 is the answer

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