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Law Incorporation [45]
3 years ago
7

How can i do this? I need do this

Mathematics
1 answer:
Wittaler [7]3 years ago
7 0

It's a little hard to read, but I think I can help you.

a) (2^9*2^11*2^3)/(2^7)^3

(2^(9+11+3))/(2^(7*3)) Remember (a^b)^c=a^(b*c) and a^b*a^c=a^(b+c)

2^23/2^21

2^(23-21) <- Exponents with the same base when divided get subtracted

2^2

4 is the answer

b) ((0.4^2)^10)/(0.4^9*0.4^7*0.4)

0.4^(2*10)/0.4^(9+7+1)

0.4^20/0.4^17

0.4^3

0.064 is the answer

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kykrilka [37]

Answer:

x + 1/4

Step-by-step explanation:

6 0
3 years ago
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For a certain model of car the distance d required to stop the vehicle if it is traveling at v mi/h is given by the formula d =
enyata [817]
Given that <span>For a certain model of car the distance d required to stop the vehicle if it is traveling at v mi/h is given by the formula d=v+\frac{v^2}{20}, where [tex]d is measured in feet.

If Kerry wants her stopping distance not to exceed 75 ft, then the range of speeds (in mi/h) can she travel is obtained as follows:

v+ \frac{v^2}{20} \leq75 \\  \\ 20v+v^2\leq1,500 \\  \\ v^2+20v+100\leq1,500+100 \\  \\ (v+10)^2\leq1,600 \\  \\ |v+10|\leq\sqrt{1,600} \\  \\ -40\leq v+10\leq40 \\  \\ -40-10\leqv\leq v\leq40-10 \\  \\ -50\leq v\leq30

Therefore, the range of speed she can travel is v\leq30\ mi/hr
</span>
8 0
3 years ago
Wbt do i multiply 7 by to get 21 or the first number they both have the same?
zzz [600]
7*3=21....The first number they would both share would be 7
3 0
4 years ago
Please help!! I really need it.
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205 students enrolled in a freshman-level chemistry class. By the end of the semester, 4 times the number of students passed as
AlexFokin [52]

Answer: 164 students passed and 41 students failed.

Step-by-step explanation:

Let the number of students be x

x students failed, but 4 times the failed students passed.

So 4x students passed and x students failed.

4x + x = 205

5x = 205

x = 205/5

x = 41

41 times 4 is 164 and 41 times 1 is 41.

So 164 students passed and 41 students failed

3 0
3 years ago
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