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Mekhanik [1.2K]
3 years ago
9

9. A pyramid has a square base with an area

Mathematics
1 answer:
Vlad [161]3 years ago
4 0
  • Answer:

<em>48 ft</em>

  • Step-by-step explanation:

<em>A  = 144ft² = l²</em>

<em>144 = l²</em>

<em>l = √144</em>

<em>l = 12 ft</em>

<em>P = 4l</em>

<em>= 4×12ft</em>

<em>= 48 ft</em>

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Answer:

\sin e\text{ S = }\frac{3}{5}

Explanation:

Here, we want to get the value of sine S

The sine of an angle is the ratio of the opposite side to the hypotenuse side

The hypotenuse side is the side that faces the right angle which is the small box. It is the longest side of the triangle and it measures 10

The opposite is the side that faces the angle which is 6

We have the sine as:

\frac{6}{10}\text{ = }\frac{3}{5}

8 0
10 months ago
if revenue for the week is 2000 and labor cost consist of two workers earning $8 per hour who work 40 hours each week what is la
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5 0
3 years ago
Factorize 2a^2+7a-15​
loris [4]

\huge\bf  \pink {\underline{Solution :-}}

2 {a}^{2}  + 7a - 15

= 2 {a}^{2}  + 10a - 3a - 15

= 2a(a + 5) - 3(a + 5)

= (a + 5)(2a - 3)

\sf \red{Hence, Answer \:  is  \: (a + 5)(2a - 3).}

\\

\bf \purple{ \underline{ Important  \: Formulas  \: for  \: Factorization :-}}

• \:  {a}^{2}  + 2ab + {b}^{2} =  {(a + b)}^{2}

• \: (a + b)(a - b) =  {a}^{2}  -  {b}^{2}

• \:  {a}^{2} - 2 ab  +  {b}^{2}  =  {(a - b)}^{2}

• \:  {a}^{3}  + 3 {a}^{2} b + 3a {b}^{2}  +  {b}^{3} =  {(a + b)}^{3}

• \:  {a}^{3}   -  3 {a}^{2} b + 3a {b}^{2}   -  {b}^{3} =  {(a  - b)}^{3}

•  \:  {(a + b)}^{2}  +  {(a - b)}^{2}  = 2( {a}^{2}  +  {b}^{2} )

• \: {(a + b)}^{2}   -   {(a - b)}^{2}  = 4ab

• \: (a + b)( {a}^{2}   -ab   +  {b}^{2}  ) =  {a}^{3}  +  {b}^{3}

• \: (a  -  b)( {a}^{2}    + ab   +  {b}^{2}  ) =  {a}^{3}   -  {b}^{3}

• \:   {( \frac{a + b}{2} )}^{2}  - ( {\frac{a - b}{2} } )^{2}  = ab

5 0
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What is the value of f-1(4)
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Answer:

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3 years ago
Select the correct answer from each drop-down menu. Trapezoid PQRS be inscribed in a circle because the .
prisoha [69]

Trapezoid PQRS be inscribed in a circle because its opposite angles are supplementary.

According to the statement

we have given that the Trapezoid PQRS be inscribed in a circle and we have to find the correct answer from the given data.

So, For this purpose, we know that the

The inscribed quadrilateral conjecture states that the opposite angle of any inscribed quadrilateral are supplementary to each other. That is, they have a sum of 180 degrees.

From the diagram given,

the opposite angles in the trapezoid are 115 and 65 degree.

So, after adding it become

115 + 65 = 180 degrees.

Therefore, we can conclude that: trapezoid QPRS can be inscribed in a circle because its opposite angles are supplementary.

So, Trapezoid PQRS be inscribed in a circle because its opposite angles are supplementary.

Learn more about inscribed quadrilateral conjecture here

brainly.com/question/12238046

Disclaimer: This question was incomplete. Please find the full content below.

Question:

Select the correct answer from each drop-down menu.

Trapezoid PQRS

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be inscribed in a circle because the

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115⁰

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65°

For more understanding please see the image below.

#SPJ4

3 0
1 year ago
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