Evaluate x^3 - 3y when x = -3 and y = 4. -39 -15 15 39

Mathematics

2 answers:

liq [111]3 years ago

8 0

Answer:

-39

Step-by-step explanation:

-3^3 - (3 * 3)

-3^ 3 = -27

-27 - (3 * 4)

3 * 4 = 12

-27 - 12

-39

Hope I helped!

abruzzese [7]3 years ago

5 0

(-3)^3 = -27 and 3y= 12

Therefore subtracting the terms,

-27-12 =-39

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borishaifa [10]

Answer:

2/5

Step-by-step explanation:

If we convert 1/2 to tenths we get 5/10. We can subtract that from 9/10 to find out what q equals which will give us 4/10 which is also equal to 2/5

(sorry i'm really bad at explaining but I hope this helps)

5 0

3 years ago

Answer this question. please

dimaraw [331]

Answer:

$\boxed{\textsf{ The total surface area of the cuboid is \textbf{62 cm} $\sf ^2$ .}}$

Step-by-step explanation:

Given that the base area of the cuboid is 7cm² . And it's volume is 21cm³ . We need to find its total surface area . Now here we need to find the height . We can find height as ,

Height :-

$\qquad\boxed{\boxed{\sf Height =\dfrac{ Volume}{Area } }}$

$\sf\implies Height =\dfrac{Volume}{Area} \\\\\sf\implies h =\dfrac{ 21cm^3}{7cm^2}\\\\\implies \boxed{ \pink{\frak { Height = 3 cm.}}}$

$\rule{200}2$

Let's find out the Total surface area .

TSA of cuboid :-

$\qquad\boxed{\boxed{\sf TSA_{(cuboid)} =2(lb + bh + hl ) }}$

Put on the respective values :-

$\sf\implies TSA_{(cuboid)}= 2( lb + bh + hl )\\\\\sf\implies TSA_{(cuboid)}= 2( 7cm\times 1cm + 1cm\times 3cm + 3cm \times 7 cm ) \\\\\sf\implies TSA_{(cuboid)}=2 ( 7cm ^2+3cm^2+21cm^2 ) \\\\\sf\implies TSA_{(cuboid)}= 2\times 31cm^2 \\\\\sf\implies \boxed{\pink{\frak{ TSA_{(cuboid)}= 62 cm^2}}}$