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GaryK [48]
3 years ago
10

4). A piece of wire in the shape of an arc of a circle

Mathematics
1 answer:
STALIN [3.7K]3 years ago
7 0

Answer:

The angle the wire now subtends at the center of the new circle is approximately 145.7°

Step-by-step explanation:

The radius of the arc formed by the piece of wire = 15 cm

The angle subtended at the center of the circle by the arc, θ = 68°

The radius of the circle to which the piece of wire is reshaped to = 7 cm

Let 'L' represent the length of the wire

By proportionality, we have;

L = (θ/360) × 2 × π × r

L = (68/360) × 2 × π × 15 cm = π × 17/3 = (17/3)·π cm

Similarly, when the wire is reshaped to form an arc of the circle with a radius of 7 cm, we have;

L = (θ₂/360) × 2 × π × r₂

∴ θ₂ = L × 360/(2 × π × r₂)

Where;

θ₂ = The angle the wire now subtends at the center of the new circle with radius r₂ = 7 cm

π = 22/7

Which gives;

θ₂ = (17/3 cm) × (22/7) × 360/(2 × (22/7) × 7 cm) ≈ 145.7°.

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The probability that a professor arrives on time is 0.8 and the probability that a student arrives on time is 0.6. Assuming thes
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Answer:

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Step-by-step explanation:

Given data

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P(A) = 0.8

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Part b)

The probability that the student is late given that the professor is on time

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Part c)

Assume the events are not independent

Given Data

P(\frac{{A}'}{{B}'}) = 0.4

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ii)The probability that they are both on time

P(A\cap  B) = 1 - P({A}'\cup {B}') = 1 - [P({A}')+P({B}') - P({A}'\cap {B}')]

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