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GaryK [48]
3 years ago
10

4). A piece of wire in the shape of an arc of a circle

Mathematics
1 answer:
STALIN [3.7K]3 years ago
7 0

Answer:

The angle the wire now subtends at the center of the new circle is approximately 145.7°

Step-by-step explanation:

The radius of the arc formed by the piece of wire = 15 cm

The angle subtended at the center of the circle by the arc, θ = 68°

The radius of the circle to which the piece of wire is reshaped to = 7 cm

Let 'L' represent the length of the wire

By proportionality, we have;

L = (θ/360) × 2 × π × r

L = (68/360) × 2 × π × 15 cm = π × 17/3 = (17/3)·π cm

Similarly, when the wire is reshaped to form an arc of the circle with a radius of 7 cm, we have;

L = (θ₂/360) × 2 × π × r₂

∴ θ₂ = L × 360/(2 × π × r₂)

Where;

θ₂ = The angle the wire now subtends at the center of the new circle with radius r₂ = 7 cm

π = 22/7

Which gives;

θ₂ = (17/3 cm) × (22/7) × 360/(2 × (22/7) × 7 cm) ≈ 145.7°.

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Step-by-step explanation:

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3 years ago
90. The number of daily evening newspapers in the United States has decreased by 46.5% to
aleksandr82 [10.1K]

Answer:

700

Step-by-step explanation:

Given:

Daily evening newspapers in 2015 = 389

Percentage decrease from 2000 to 2015 = 46.5%

To find:

Number of newspapers in 2000 = ?

Solution:

Let the number of newspapers in 2000 = x

When 46.5% of the total newspapers in 2000 (x) is subtracted from the total  newspapers in 2000 (x), it will be equal to the number of newspapers in 2015.

Making the equation as per the given statement:

x-x\times 46.5\%=389\\\Rightarrow \dfrac{100x-46.5x}{100}=389\\\Rightarrow 53.5x=38900\\\Rightarrow x\approx \bold{727}

Therefore, the answer is:

There were <em>727 </em>newspapers in 2000.

7 0
3 years ago
Find the value of x
fgiga [73]

\qquad \qquad  \bf \huge\star \:  \:  \large{  \underline{Answer} }  \huge \:  \: \star

  • x = 35°

\textsf{  \underline{\underline{Steps to solve the problem} }:}

\qquad❖ \:  \sf \:4x + 1 + x + 4 = 180

[ by linear pair ]

\qquad❖ \:  \sf \:5x + 5 = 180

\qquad❖ \:  \sf \:5(x + 1) = 180

\qquad❖ \:  \sf \:x + 1 = 180 \div 5

\qquad❖ \:  \sf \:x + 1 = 36

\qquad❖ \:  \sf \:x = 36 - 1

\qquad❖ \:  \sf \:x = 35

\qquad \large \sf {Conclusion}  :

  • x = 35°
7 0
2 years ago
A geometric sequence is defined by the general term tn = 75(5n), where n ∈N and n ≥ 1. What is the recursive formula of the sequ
andreyandreev [35.5K]
The correct answer is C) t₁ = 375, t_n=5t_{n-1}.

From the general form,
t_n=75(5)^n, we must work backward to find t₁.

The general form is derived from the explicit form, which is
t_n=t_1(r)^{n-1}.  We can see that r = 5; 5 has the exponent, so that is what is multiplied by every time. This gives us

t_n=t_1(5)^{n-1}

Using the products of exponents, we can "split up" the exponent:
t_n=t_1(5)^n(5)^{-1}

We know that 5⁻¹ = 1/5, so this gives us
t_n=t_1(\frac{1}{5})(5)^n&#10;\\&#10;\\=\frac{t_1}{5}(5)^n

Comparing this to our general form, we see that
\frac{t_1}{5}=75

Multiplying by 5 on both sides, we get that
t₁ = 75*5 = 375

The recursive formula for a geometric sequence is given by
t_n=t_{n-1}(r), while we must state what t₁ is; this gives us

t_1=375; t_n=t_{n-1}(5)

3 0
3 years ago
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artcher [175]
Y=7x+9 here’s your answer
5 0
3 years ago
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