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4 years ago

7

Chloe practices piano an average of 8 hours per week. Patricia practices figure skating an average of 1.2 hours for every hour C

hloe practices. How many hours a week does Patricia practice?

1 answer:

Thepotemich [5.8K]4 years ago

3 0

8×1.2=9.6
$8 \times 1.2 = 9.6$

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On a coordinate plane, a line is drawn from point A to point B. Point A is at (2, negative 3) and point B is at (negative 4, 9).

zimovet [89]

Answer: (0,1)

Step-by-step explanation:

If $(x_1, y_1)$ and $(x_2, y_2)$ are two point son a coordinate plane and (x,y) dividing it in a ratio of m: n.

Then , the coordinates of (x,y) is given by :-

$x=\dfrac{nx_1+mx_2}{m+n}$

$y=\dfrac{ny_1+my_2}{m+n}$

Given : On a coordinate plane, a line is drawn from point A to point B. Point A is at (2, - 3) and point B is at (- 4, 9).

Then , the x- and y- coordinates of point E, which partitions the directed line segment from A to B into a ratio of 1:2 :

$x=\dfrac{2(2)+1(-4)}{1+2}=0$

$y=\dfrac{2(-3)+1(9)}{1+2=1}$

Hence, the x- and y- coordinates of point E = (0,1)

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4 years ago

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3(2-3+4) <br><br>math problem help me to slove

mel-nik [20]

Answer:

9 is the answer

Step-by-step explanation:

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3 years ago

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After how many years are the salaries offered by company a and company b the same

12345 [234]

24000 + 3000x = 30000 + 2400x
3000x - 2400x = 30,000 - 24,000
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3 years ago

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andrezito [222]

The correct equation that models for this problem is x over y or x/y.
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4 years ago

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How much longer is the hypotenuse of the triangle than its shorter leg?

RUDIKE [14]

This is an incomplete question, here is a complete question and image is also attached below.

How much longer is the hypotenuse of the triangle than its shorter leg?

a. 2 ft

b. 4 ft

c. 8 ft

d. 10 ft

Answer : The correct option is, (b) 4 ft

Step-by-step explanation:

Using Pythagoras theorem in ΔACB :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(AB)^2=(AC)^2+(BC)^2$

Given:

Side AC = 6 ft

Side BC = 8 ft

Now put all the values in the above expression, we get the value of side AB.

$(AB)^2=(6)^2+(8)^2$

$AB=\sqrt{(6)^2+(8)^2}$

$AB=10ft$

Now we have to calculate the how much longer is the hypotenuse of the triangle than its shorter leg.

Difference = Side AB - Side AC

Difference = 10 ft - 6 ft

Difference = 4 ft

Therefore, the 4 ft longer is the hypotenuse of the triangle than its shorter leg.

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