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marysya [2.9K]
3 years ago
6

What is the inverse of the given relation? y=3x+12

Mathematics
2 answers:
stich3 [128]3 years ago
6 0

For this case we have the following function:

y = 3x + 12

We change the variables:

x = 3y + 12

From here, we clear the value of y.

3y = x-12\\y = \frac {x} {3} -4

Then, we make the following change:

y = f (x) ^ {-1}

Finally, the inverse function is:

f (x) ^ {- 1} = \frac {x} {3} -4

Answer:

The inverse of the given relation is:

f (x) ^ {- 1} = \frac {x} {3} -4

vladimir1956 [14]3 years ago
6 0
We have to find the inverse of the relation : y = 3 x + 12First we have to switch x and y:x =  3 y + 12- 3 y = - x + 12  / * ( - 1 )     ( multiply both sides by - 1 )
3 y = x - 12   / : 3                 ( divide both sides by 3 )y = x / 3 - 4Answer:The inverse of the given relation is  y = x / 3 - 4. 

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Solve the system using elimination
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-4x + 9y = -22

-9x -9y = 126

-13x = 104

x = -8

8 +`y = 14

y = 6

(-8,6)

6 0
3 years ago
A market research firm supplies manufacturers with estimates of the retail sales of their products from samples of retail stores
KengaRu [80]

Answer:

The 95% confidence interval for the difference of means is (7.67, 16.33).

The estimate is Md = 12.

The standard error is sM_d = 2.176.

Step-by-step explanation:

We have to calculate a 95% confidence interval for the difference between means.

The sample 1 (this year's sales), of size n1=36 has a mean of 53 and a standard deviation of 12.

The sample 2 (last year's sales), of size n2=49 has a mean of 41 and a standard deviation of 6.

The difference between sample means is Md=12.

M_d=M_1-M_2=53-41=12

The estimated standard error of the difference between means is computed using the formula:

s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{12^2}{36}+\dfrac{6^2}{49}}\\\\\\s_{M_d}=\sqrt{4+0.735}=\sqrt{4.735}=2.176

The degrees of freedom are:

df=n_1+n_2-1=36+49-2=83

The critical t-value for a 95% confidence interval and 83 degrees of fredom is t=1.989.

The margin of error (MOE) can be calculated as:

MOE=t \cdot s_{M_d}=1.989 \cdot 2.176=4.328

Then, the lower and upper bounds of the confidence interval are:

LL=M_d-t \cdot s_{M_d} = 12-4.328=7.67\\\\UL=M_d+t \cdot s_{M_d} = 12+4.328=16.33

The 95% confidence interval for the difference of means is (7.67, 16.33).

7 0
3 years ago
The Bourassas decide to sell a home for $440,000. They are charged a real estate commission of 8% of the selling price, title in
ololo11 [35]

The amount received net of expenses is $397865 and the percentage of the sale price was 10%.

Given that Bourassas decides to sell a house for $ 440,000. You will be charged a real estate fee of 8% of the sale price, property insurance of 1.4% of the sale price, and an escrow fee of $ 775.

The declared retail price is $ 440,000.

Real estate commission = 8% of the sale price

Real Estate Fee = (8/100) × 440000

Real Estate Fee = 8 × 4400

Real Estate Fee = $ 35,200

Security insurance costs of the title = 1.4% of the sale price

Cost of title insurance = (1.4 / 100) × 440 000

Cost of title insurance = 1.4 × 4400

Title Insurance Cost = $ 6160

The escrow fee assigned is $ 775.

(a) In determining the amount received after deducting the sale price of the property commission, title insurance and escrow fees, we receive

Amount received after fees = sale price - real estate commission - title insurance - escrow fees

Amount received after fees = 440000-35200-6160-775

The amount received after fees = $397865

(b) To find the percentage of sale price, add together all the terms real estate commission, title insurance and escrow fees and divide by the sale price we get

Percentage of selling price=((35200+6160+775)/440000)×100

Percentage of sale price = (42135/440000) × 100

Percentage of sale price = 9.57

Percentage of sale price = 10% (rounded down)

Hence Bourassas decides to sell a house for $440,000, then the amount Bourassas will receive after expenses is $397,865 and the percentage of the sale price of expenses is 10%.

Learn more about selling price from here brainly.com/question/11067377

#SPJ1

8 0
1 year ago
Ashton designs movie sets. For one scene, he has to hang a banner across an archway that takes the shape of a parabola modeled b
Crazy boy [7]
No question is asked so I'm not sure what you are looking for but below I calculated the point where the two equations intersect:
y - x = 4 → y = x + 4
y = - x² + 6x
x + 4 = - x² + 6x
x² - 5x + 4 = 0
(x - 4)(x - 1) = 0
 x = 4, x = 1

when x = 4, then y = x + 4 = 4 + 4 = 8 → (4,8)
when x = 1, then y = x + 4 = 1 + 4 = 5 → (1,5)

The line and parabola intersect at two points: (4,8) and (1,5)



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3 years ago
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elixir [45]

Answer:

See picture:)

Hope that makes sense! If you'd like any more help with maths, I'd be happy to offer online tuition. You can find me at: www.birchwoodtutors.com

8 0
3 years ago
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