The Answer is C
R is (2,-1)
2*2=4
-1*2=-2
2r=(4,-2)
t=(-7,5)
-7-4=-11
5-(-2)=5+2=7
t-r=(-11,7)
Since we are multiplying r by two, we have to multiply its x and y values by two to be 2r
With t-2r, we have to subtract 2r's x value from t's x value and 2r's y value fro t's y value to get the x value -11 and the y value 7
Therefore, the x and y values for the answer is -11 and 7, and to put them in the proper form required, which is (x,y), input -11 into x's spot and 7 in y's spot, giving you and answer of (-11,7)
The Answer to this question is X= -10
4.5(8-x)+36=102-2.5(3x+24)
36-4.5x+36=102-7.5x-60
72-4.5x=42-7.5x
-4.5+7.5x=42-72
8x=30
x=-10
Hope this Helps and There the Work that got you the answer
You have 22+3x/3x+7=2. That 3x/3x raises eyebrows; is this what you meant, with the result that 3x/3x = 1? or did you mean
3x
22 + ------------- + 7 = 2?
3x+7
If you meant the latter, then simplify the equation by subtracting 2 from both sides:
3x
27 + ---------- = 0
3x+7
Multiply all three terms by (3x+7), obtaining
27(3x+7) + 3x = 0
Then 21x + 3x + 189 = 0, so that 24x = -189, or x = -189/24 = -7 7/8
Answer:
C) Has a standard deviation of return of zero
Step-by-step explanation:
A riskfree asset is one in which return is certain in the future. With a standard deviation of zero, it means that there is certainty for return in investment.
The numbers are: "3" and "9" .
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Explanation:
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Let "x" represent one of the two (2) numbers.
Let "y" represent the other one of the two (2) numbers.
x = 2y + 3 ;
x + y = 12 .
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Method 1)
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x = 12 <span>− y ;
Plug this into "x" for "2y + 3 = x" ;
</span>→ 2y + 3 = 12 <span>− y ;
</span>
Add "y" to each side of the equation; & subtract "3" from each side of the equation ;
→ 2y + 3 + y − 3 = 12 − y + y <span>− 3 ;
</span>
to get: 3y = 9 ;
Divide each side of the equation by "3" ;
to isolate "y" on one side of the equation; & to solve for "y" ;
3y / 3 = 9 / 3 ;
y = 3 .
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Now: x = 12 − y ; Plug in "3" for "y" ; to solve for "x" ;
→ x = 12 − 3 = 9
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So; x = 9, y = 3 .
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Method 2)
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When we have:
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x = 2y + 3 ;
x + y = 12 .
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→ y = 12 − x ;
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Substitute "(12−x)" for "y" in the equation:
" x = 2y + 3 " ;
→ x = 2(12 − x) + 3 ;
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Note the "distributive property of multiplication" :
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a(b + c) = ab + ac ;
a(b − c) = ab − ac ;
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As such:
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→ 2(12 − x) = 2(12) − 2(x) = 24 − 2x ;
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So; rewrite:
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x = 2(12 − x) + 3 ;
as:
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→ x = 24 − 2x + 3 ;
→ x = 27 − 2x ;
Add "2x" to each side of the equation:
→ x + 2x = 27 − 2x + 2x ;
→ 3x = 27 ;
Divide each side of the equation by "3" ;
to isolate "x" on one side of the equation; & to solve for "x" ;
3x / 3 = 27 / 3 ;
x = 9 .
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Note: "y = 12 − x" ; Substitute "9" for "x" ; to solve for "y" ;
→ y = 12 − 9 = 3 ;
→ y = 3 .
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So, x = 9 ; and y = 3.
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The numbers are: "3" and "9" .
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To check our answers:
Let us plug these numbers into the original equations;
to see if the equations hold true ; (i.e. when, "x = 9" ; and "y = 3"
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→ x + y = 12 ;
→ 9 + 3 =? 12 ? Yes!
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→ x = 2y + 3 ;
→ 9 =? 2(3) + 3 ?? ;
→ 9 =? 6 + 3 ? Yes!!
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