2
3x. + 63x + 9x + 189
Step-by-step explanation:
<em>Use</em><em> </em><em>distributive</em><em> </em><em>law</em><em>,</em><em> </em><em>in</em><em> </em><em>other</em><em> </em><em>words</em><em> </em><em>multiply</em><em> </em><em>the</em><em> </em><em>first</em><em> </em><em>bracket</em><em> </em><em>terms</em><em> </em><em>by</em><em> </em><em>the</em><em> </em><em>second</em><em> </em><em>bracket</em><em> </em><em>terms</em><em> </em>
Answer:
Between 38.42 and 49.1.
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
Approximately 68% of the measures are within 1 standard deviation of the mean.
Approximately 95% of the measures are within 2 standard deviations of the mean.
Approximately 99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean of 43.76, standard deviation of 2.67.
Between what two values will approximately 95% of the amounts be?
By the Empirical Rule, within 2 standard deviations of the mean. So
43.76 - 2*2.67 = 38.42
43.76 + 2*2.67 = 49.1
Between 38.42 and 49.1.
Flip the fraction to make the -3 exponet positive then it will be 9x^5/3x^3 which the answer would then be 3x^2
Answer:
us
Step-by-step explanation:
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