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Answer:
The correct option is B.
Step-by-step explanation:
Given information: AB\parallel DCAB∥DC and BC\parallel ADBC∥AD .
Draw a diagonal AC.
In triangle BCA and DAC,
AC\cong ACAC≅AC (Reflexive Property of Equality)
\angle BAC\cong \angle DCA∠BAC≅∠DCA ( Alternate Interior Angles Theorem)
\angle BCA\cong \angle DAC∠BCA≅∠DAC ( Alternate Interior Angles Theorem)
The ASA (Angle-Side-Angle) postulate states that two triangles are congruent if two corresponding angles and the included side of are congruent.
By ASA postulate,
\triangle BCA\cong \triangle DAC△BCA≅△DAC
Therefore option B is correct
Answer:
d. does not exist
Step-by-step explanation:
The given limits are;
,
and 
We want to find

By the properties of limits, we have;

This gives us;

Division by zero is not possible. Therefore the limit does not exist.
Answer:
126.73
Step-by-step explanation:
5.03+13.7+108
5.03+13.7= 18.73
18.73 +108=
126.73