Answer:
True
Step-by-step explanation:
The pages left = total pages - the pages read
(10b + 3) - (-2b +78)
10b + 2b + 3 - 78
12b - 75
The pages left is equal to 12b - 75
 
        
             
        
        
        
<span>60
Sorry, but the value of 150 you entered is incorrect. So let's find the correct value.
The first thing to do is determine how large the Jefferson High School parking lot was originally. You could do that by adding up the area of 3 regions. They would be a 75x300 ft rectangle, a 75x165 ft rectangle, and a 75x75 ft square. But I'm lazy and another way to calculate that area is take the area of the (300+75)x(165+75) ft square (the sum of the old parking lot plus the area covered by the school) and subtract 300x165 (the area of the school). So
(300+75)x(165+75) - 300x165 = 375x240 - 300x165 = 90000 - 49500 = 40500
So the old parking lot covers 40500 square feet. Since we want to double the area, the area that we'll get from the expansion will also be 40500 square feet. So let's setup an equation for that:
(375+x)(240+x)-90000 = 40500
The values of 375, 240, and 90000 were gotten from the length and width of the old area covered and one of the intermediate results we calculated when we figured out the area of the old parking lot. Let's expand the equation:
(375+x)(240+x)-90000 = 40500
x^2 + 375x + 240x + 90000 - 90000 = 40500
x^2 + 615x = 40500
x^2 + 615x - 40500 = 0
Now we have a normal quadratic equation. Let's use the quadratic formula to find its roots. They are: -675 and 60. Obviously they didn't shrink the area by 675 feet in both dimensions, so we can toss that root out. And the value of 60 makes sense. So the old parking lot was expanded by 60 feet in both dimensions.</span>
        
             
        
        
        
The area of the polygons compare to π in the way that as
more angles and sides are added to a polygon the polygon becomes closer to a
circle; the perimeter slowly changes to circumference. Π is used to find the
area and circumference of a circle, so as polygons come closer to becoming circles
π becomes more strongly associated to the polygon. You can even use π to find
the approximate area of a circle if you use the same formula (as you would to
find the area of a circle) on a polygon. Another way to go about it is like
this…
You can find the area of a circle if you know the circle’s
circumference by using these steps:
<span>1.         Divide the
circumference by π to find the diameter of the circle.</span>
<span>2.         Divide the
diameter by 2 to find the radius of the circle.</span>
<span>3.         Now that you
have the radius you can use the formula Area= πr2 to find the area of the
circle.</span>
 
        
                    
             
        
        
        
Answer:
180+54sqrt3
You have to use the formula that is contained within the lessons, the answer you should have before you format it like this is: 273.530743609
 
        
             
        
        
        
Answer:
The radius of the inner circle is 14 ft. Since the outer circle is 3 ft more than the inner circle, its radius is 17 ft. The circumference formula is 2(pi)radius (or 2(22/7)17 in this case). The circumference of the outer circle is 106.85 ft (or 106.9 if rounding). To find the difference, you would subtract the smallest FROM the greatest:
106.85 - 88 = 18.85 ft (or 18.9 if rounding)