Question

The scores of the athletes are 32,45,33,22,50,48. Find the variance.

Answer 1

Answer:

Step-by-step explanation:

First, find the mean ; (32+45+33+22+50+48) / 6 = 230/6

Mean = 38.33

Variance =$\frac{SUM(X-meanX)^{2} }{n-1}$

n = sample size

Variance = $\frac{(32-38.33)^{2} +(45-38.33)^{2}+(33-38.33)^{2} +(22-38.33)^{2}+(50-38.33)^{2}+(48-38.33)^{2} }{5}$

Variance = $\frac{(44.4889 +40.0689 +28.4089 + 266.6689 +136.1889 +93.5089)}{5}$

= $\frac{609.3334}{5}$

= 121.8667

Therefore, variance = 121.87