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Anvisha [2.4K]
4 years ago
7

The scores of the athletes are 32,45,33,22,50,48. Find the variance.

Mathematics
1 answer:
Grace [21]4 years ago
6 0

Answer:

Step-by-step explanation:

First, find the mean ; (32+45+33+22+50+48) / 6 = 230/6

Mean = 38.33

Variance =\frac{SUM(X-meanX)^{2} }{n-1}

n = sample size

Variance = \frac{(32-38.33)^{2} +(45-38.33)^{2}+(33-38.33)^{2} +(22-38.33)^{2}+(50-38.33)^{2}+(48-38.33)^{2} }{5}

Variance = \frac{(44.4889 +40.0689 +28.4089 + 266.6689 +136.1889 +93.5089)}{5}

= \frac{609.3334}{5}

= 121.8667

Therefore, variance = 121.87

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