Answer:
Explanation:
given ;
- coefficient of kinetic friction = 0.80
- considering the force acting in horizontal direction and from newton's 2nd law of motion;
- for vertical motion = Fn - mg = 0
- for horizontal motion = F = ma + miu mg = m( a + miu.g)
- therefore, F = miu mg where g = 9.81m/s^2
- plugging the values into the equation;
Horizontal force = 204.05N
Answer:
If gravity on Earth is increased, this gravitational tugging would have influenced the moon's rotation rate. If it was spinning more than once per orbit, Earth would pull at a slight angle against the moon's direction of rotation, slowing its spin. If the moon was spinning less than once per orbit, Earth would have pulled the other way, speeding its rotation.
Answer:
80 ft/s
Explanation:
Given:
Δy = 100 ft
v₀ = 0 ft/s
a = 32.2 ft/s²
Find: v
v² = v₀² + 2aΔx
v² = (0 ft/s)² + 2 (32.2 ft/s²) (100 ft)
v = 80.2 ft/s
Rounded, the speed when it reaches the ground is 80 ft/s.
Answer:
C
Explanation:
There's a reason newton's 3rd law is called action-reaction :D
A - 1st law/inertia
B - 2nd law/f=ma
We know the equation of motion v = u+ at, where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.
In this case Final velocity before collision = 115 km/hr = 115*5/18 = 31.94 m/s
Time taken by car to reach this velocity = 8.83 seconds
Initial velocity = 0 m/s
v = u +at
31.94 = 0 + a*8.83
a = 3.62 
So acceleration of car just before collision = 3.62
