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lorasvet [3.4K]
3 years ago
7

Along the remote Racetrack Playa in Death valley, California,stones sometimes gouge out prominent trails in the desert floor, as

if they had been migrating. For years curiosity mounted about whythe stones moved. One explanation was that strong winds during theoccasional rainstorms would drag the rough stones over groundsoftened by rain. When the desert dried out, the trails behind thestones were hard-baked in place. According to measurements, thecoefficient of kinetic friction between the stones and the wetplaya ground is about 0.80. What horizontal force is needed on a26 kg stone (a typical mass) to maintainthe stone's motion once a gust has started it moving?
Physics
1 answer:
MArishka [77]3 years ago
3 0

Answer:

Explanation:

given ;

  • coefficient of kinetic friction = 0.80
  • mass m = 26kg
  • considering the force acting in horizontal direction and from newton's 2nd law of motion;
  • for vertical motion = Fn - mg = 0
  • for horizontal motion = F = ma + miu mg = m( a + miu.g)
  • but a = 0
  • therefore, F = miu mg where g = 9.81m/s^2
  • plugging the values into the equation;
  • F = 0.80 x 9.81 x 26

Horizontal force = 204.05N

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Suppose humans have weights which are normally distributed with mean 170 lbs and SD 50 lbs. If 400 humans are selected at random
MrRa [10]

Answer:

 P(x< 175)= 0.9772

Explanation:

given,

mean weight of human = μ = 170 lbs

standard deviation = SD = 50 lbs

N = 400 humans

By using central limit theorem,

P (x< 175)

P(x< 175)= P(z

P(x< 175)= P(z

P (x< 175)= P(z

P (x< 175)= P(z

using z-table

 P (x< 175)= 0.9772

hence, the probability that total weight is less tan 175 lbs is equal to

 P(x< 175)= 0.9772

7 0
3 years ago
A penny is placed on a rotating turntable. Where on the turntable does the penny require the largest centripetal force to remain
Artyom0805 [142]

Answer:

m = mass of the penny

r = distance of the penny from the center of the turntable or axis of rotation

w = angular speed of rotation of turntable

F = centripetal force experienced by the penny

centripetal force "F" experienced by the penny of "m" at distance "r" from axis of rotation is given as

F = m r w²

in the above equation , mass of penny "m"  and angular speed "w" of the turntable is same at all places. hence the centripetal force directly depends on the radius .

hence greater the distance from center , greater will be the centripetal force to remain in place.  

So at the edge of the turntable , the penny experiences largest centripetal force to remain in place.

Explanation:

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3 years ago
What is the mass of an object with 15,000 J of kinetic energy moving at 20 m/s?
insens350 [35]

Answer:

kE=1/2mv^2

Explanation:

here

KE= 15000j

velocity =20m/s

mass=?

now

mass=

15000×2= (m)20^2

30000=m ×400

30000÷400=m

Mass (m)= 75

therefore mass is 75kilogram

6 0
3 years ago
Marvin the Martian needs to get back home. Marvin is 321,770 m from his home on Mars. He decides the quickest way to get home is
Liono4ka [1.6K]

Answer:

y = 14238 m.    the height of the rocket is much less than this distance therefore the plan will not work.

Explanation:

Let's analyze this exercise, so that the Martian's plan works, the vertical height of the body must be zero when it is more than half of the way to the planet Mars, this is so that Mars attracts it and can arrive.

Let's calculate the maximum height of the launch

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at the highest point v_{y} = 0

          y = v_{oy}² / 2g

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let's calculate

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In the exercise, indicate that the distance to Mars is h = 321770 m, half of this distance is

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therefore the height of the rocket is much less than this distance therefore the plan will not work.

The height reached is low, so it is not necessary to take into account the variation of g with height

8 0
3 years ago
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Setler79 [48]

She need to release the cluch slowly and apply force on the accelator other than place her vehicle's gear in Drive and accelerate

<h3>How we drive a car?</h3>

We drive a car by applying pressure on the accelator, remove foot from the brakes and releasing cluch slowly. When the vehicle get speed, we have to change the gear.

So we can conclude that She need to release the cluch slowly and apply force on the accelator for driving a car.

Learn more about accelaration here: brainly.com/question/605631

4 0
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