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lorasvet [3.4K]
3 years ago
7

Along the remote Racetrack Playa in Death valley, California,stones sometimes gouge out prominent trails in the desert floor, as

if they had been migrating. For years curiosity mounted about whythe stones moved. One explanation was that strong winds during theoccasional rainstorms would drag the rough stones over groundsoftened by rain. When the desert dried out, the trails behind thestones were hard-baked in place. According to measurements, thecoefficient of kinetic friction between the stones and the wetplaya ground is about 0.80. What horizontal force is needed on a26 kg stone (a typical mass) to maintainthe stone's motion once a gust has started it moving?
Physics
1 answer:
MArishka [77]3 years ago
3 0

Answer:

Explanation:

given ;

  • coefficient of kinetic friction = 0.80
  • mass m = 26kg
  • considering the force acting in horizontal direction and from newton's 2nd law of motion;
  • for vertical motion = Fn - mg = 0
  • for horizontal motion = F = ma + miu mg = m( a + miu.g)
  • but a = 0
  • therefore, F = miu mg where g = 9.81m/s^2
  • plugging the values into the equation;
  • F = 0.80 x 9.81 x 26

Horizontal force = 204.05N

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Answer:

B. - 0.328

Explanation

Potential Energy:<em> This is the energy of a body due to position.</em>

<em>The S.I unit of potential energy is Joules (J).</em>

<em>It can be expressed mathematically as</em>

<em>Ep = mgh........................... Equation 1</em>

<em>Where Ep = potential energy, m = mass of the coin, h = height, g = acceleration due to gravity,</em>

<em>Given: m = 2.74 g = 0.00274 kg, h = 12.2 m, g = 9.8 m/s²</em>

Substituting these values into equation 1

Ep = 0.00274×12.2×9.8

Ep = 0.328 J.

Note: Since the potential energy at the surface is zero, the potential Energy with respect to the surface = -0.328 J

The right option is B. - 0.328

<em />

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3 years ago
A gas exerts less pressure when it has a
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I can't seem to get the right angular acceleration and also not sure how to do part b. Help will be much appreciated.
Tcecarenko [31]

Answer:It’s 5 I believe

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8 0
3 years ago
Calculate the de Broglie wavelength of (a) a mass of 1.0 g traveling at 1.0 m s−1 , (b) the same, traveling at 1.00 × 105 km s−1
lesantik [10]

Answer:

a)\lambda=6.63\times10^{-31}m

b)\lambda=6.63\times10^{-39}m

c)\lambda=9.97\times10^{-11}m

d)\lambda=4.03\times10^{-36}m

e)λ=∞

Explanation:

De Broglie discovered that an electron or other mass particles can have a wavelength associated, and that wavelength (λ) is:

\lambda=\frac{h}{P}=\frac{h}{mv}

with h the Plank's constant (6.63\times10^{-34}\frac{m^{2}kg}{s}) and P the momentum of the object that is mass (m) times velocity (v).

a)\lambda=\frac{6.63\times10^{-34}}{(1.0\times10^{-3}kg*1.0)}

\lambda=6.63\times10^{-31}m

b)\lambda=\frac{6.63\times10^{-34}}{(1.0\times10^{-3}*(1.00\times10^{8}))}

\lambda=6.63\times10^{-39}m

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e) \lambda=\frac{6.63\times10^{-34}}{(74*0)}

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Answer:

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v=(18200 x 16.5)/0.142

v is the answer for baseball

Explanation:

⚠️not my answer tryna be honest here⚠️

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