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Setler79 [48]
4 years ago
8

An initially motionless test car is accelerated uniformly to 115 km/h in 8.83 seconds before striking a simulated deer. The car

is in contact with the faux fawn for 0.995 seconds, after which the car is measured to be traveling at 60.0 km/h. What is the magnitude of the acceleration of the car before the collision?
Physics
1 answer:
goblinko [34]4 years ago
3 0

We know the equation of motion v = u+ at, where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.

In this case Final velocity before collision = 115 km/hr = 115*5/18 = 31.94 m/s

Time taken by car to reach this velocity = 8.83 seconds

Initial velocity = 0 m/s

v = u +at

31.94 = 0 + a*8.83

a = 3.62 m/s^2

So acceleration of car just before collision = 3.62 m/s^2

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Nadya [2.5K]

Answer:

Protecting the Seashore

Seashore Conservation Code

When investigating a seashore it is important to remember that the welfare of the plants and animals must come first. If seaweeds are attached to rocks do not try to pull them off, just examine them where they are growing. Handle animals with great care, returning them to the place where they were found. Anemones and limpets are normally firmly stuck to rocks and any attempt to remove them may result in their death. Replace any large stones that are removed – animals that live on the underside soon die if left exposed.

Pollution Problems

Seas and seashores are under continual threat from pollution. Here are some examples:-

oil rigOil spills, either accidental or deliberate, have a devastating effect on marine life, especially seabirds. Black tar-like oil washed up on a rocky shore would obviously completely destroy the entire community of living things. Chemicals used to disperse oil spills on a shore may effectively clean up the oil, but they can also cleanse the shore of life! The best policy for marine life is to physically remove as much oil as possible and leave the rest to degrade naturally. A rocky shore will recover much more quickly if chemicals are not used.

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Explanation:

5 0
3 years ago
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Ten seconds after starting from rest, a freely-falling object will have a speed of about ________________________
yaroslaw [1]

Answer:

100 m/s

Explanation:

Speed increases at a rate of 10 m/s (actually 9.8 m/s) every second. Thus after 10 seconds, the speed is 10 x 10 = 100 m/s.

6 0
3 years ago
A skateboarder jumps horizontally off the top of a staircase at a speed of 14.5 – and lands at bottom of the
Marrrta [24]

Question:

A skateboarder jumps horizontally off the top of a staircase at a speed of 14.5 and lands at bottom of the stairs. The staircase has a horizontal length of 8.00 m. We can ignore air resistance. What is the skater's vertical displacement during the jump?

Answer:

y = 1.48 m

Explanation:

Projectile motion is a two dimensional motion experienced by an object or particle that is subjected near the Earth's surface and moves along a curved path under the influence of gravity only. The path followed by projectile motion is called projectile path.

As the skateboarder followed the projectile path, and we know that in projectile motion the horizontal component of the velocity remain constant throughout his motion. So there is no acceleration along horizontal path.

Also Skateboard jumps horizontally, So initial velocity has only horizontal component.

Horizontal component of initial velocity = v_{i_{x}} = 14.5 m/s

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As v_{i_{y}} = 0

So

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y = 0.5*9.8*(0.55)²

y = 1.48 m

8 0
3 years ago
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This can be solve by using the formula

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I = 0.36

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