An initially motionless test car is accelerated uniformly to 115 km/h in 8.83 seconds before striking a simulated deer. The car
1 answer:
We know the equation of motion v = u+ at, where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.
In this case Final velocity before collision = 115 km/hr = 115*5/18 = 31.94 m/s
Time taken by car to reach this velocity = 8.83 seconds
Initial velocity = 0 m/s
v = u +at
31.94 = 0 + a*8.83
a = 3.62
So acceleration of car just before collision = 3.62
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But
- Hence higher the radius lower the voltage
- Lower the voltage higher the capacitance .
1)
2) 13.9 s
Explanation:
1)
The acceleration due to gravity is the acceleration that an object in free fall (acted upon the force of gravity only) would have.
It can be calculated using the equation:
(1)
where
G is the gravitational constant
is the Earth's mass
r is the distance of the object from the Earth's center
The pendulum in the problem is at an altitude of 3 times the radius of the Earth (R), so its distance from the Earth's center is
where
is the Earth's radius
Therefore, we can calculate the acceleration due to gravity at that height using eq.(1):
2)
The period of a simple pendulum is the time the pendulum takes to complete one oscillation. It is given by the formula
where
L is the length of the pendulum
g is the acceleration due to gravity at the location of the pendulum
Note that the period of a pendulum does not depend on its mass.
For the pendulum in this problem, we have:
L = 3 m is its length
is the acceleration due to gravity (calculated in part 1)
Therefore, the period of the pendulum is: