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fiasKO [112]
2 years ago
13

Write an equation for the following word problem: "the difference of twice a number and 3 is -21"

Mathematics
1 answer:
murzikaleks [220]2 years ago
4 0

Answer:

-9

Step-by-step explanation:

You might be interested in
The minute hand on a clock is 9 centimeters long and travels through an arc of 252 degrees every 42 minutes. To the nearest tent
kkurt [141]

Answer:

39.6 cm

Step-by-step explanation:

Applying

s = 2πrθ/360................ Equation 1

Where s = length of an arc or distance traveled by the minutes hand of the clock during the 42 munites, r = length of the minutes hand of the clock, θ = Angle traveled by the minute hand of the clock for every 42 minutes

From the question,

Given: r = 9 cm, θ = 252°

Constant: π = 22/7 = 3.14

Substitute these values into equation 1

s = (2×3.14×9×252)/360

s = 39.564

s = 39.6 cm

4 0
3 years ago
Yo help me out please.​
katrin2010 [14]

Answer:

12

Step-by-step explanation:

-12 = -3/4x + 3

-9 = -3/4x

-9 = (-3/4) times x

-9 = (-3/4) times 12

hope this helps! :)

6 0
3 years ago
Look at the formula for the volume of a cylinder below.
scZoUnD [109]
h = V / ( \pi r^2)

Okay, so we already have the volume equation for a cylinder here.
V = \pi r^2 h
Since we need to find the height(h), we need to basically isolate it in the equation. To do that we just have to divide both sides by (pi * r^2), where we end up with:
V / (\pi r^2) = h(\pi r^2) / (\pi r^2)
then
V / ( \pi  r^2) = h
h = V / ( \pi r^2)
8 0
2 years ago
What is the the volume of this?<br><br> Also you can explain just make the explanation short
fgiga [73]
15×20×10=3000
10×20×15=3000
3000+3000=6000 cm^{2}

6 0
3 years ago
Suppose a white dwarf star has a diameter of approximately 1.8083 to the power of 4 km. Use the formula 4n to the power of 2 to
aivan3 [116]

ANSWER:

The surface area of the star is 3.2700 x 10^{8} square kilometres.

EXPLANATIONS:

Diameter of the star = 1.8083 x 10^{4} Km.

Surface area of the star = 4n^{2}

Where n is the radius of the star.

So that;

n = \frac{ 1.8083 * 10^{4} }{2}

   = 0.90415 x 10^{4}

n =  0.90415 x 10^{4} Km

Thus,

Surface area = 4 x (0.90415*10^{4} )^{2}

                     = 326994889

Surface area = 3.2700 x 10^{8} km^{2}

Therefore, the surface area of the star is 3.2700 x 10^{8} square kilometres.

4 0
2 years ago
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