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2 years ago

SOMEONE HELP ME WITH THIS MATH PROBLEM PLEASE

Mathematics

1 answer:

Katarina [22]2 years ago

3 0

Answer:

Step-by-step explanation:

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EFGH is a parallelogram. Find the measure of FG and EG <br>

navik [9.2K]

Answer:

FG = 44

EG = 80

Step-by-step explanation:

For FG:

1) 5z - 16 = 3z + 8

2) 5z = 3z + 24

3) 2z = 24

4) z = 12

5) 3(12) + 8 = 44

For EG:

1) 2w + 22 = 4w + 4

2) 2w = 4w - 18

3) -2w = -18

4) w = 9

5) 4(9) + 4 + 2w + 22 = 80

7 0

2 years ago

Pls help!!

AleksAgata [21]

Answer:

11.25

Step-by-step explanation:

15x3/4=45/4=11.25pounds

8 0

2 years ago

SOMEONE PLEASE HELP!!!

SVETLANKA909090 [29]

ST = 1/2 (RV) = VQ = 6

answer

ST = 6

hope it helps

8 0

3 years ago

Find the mean, median, and mode of the data, if possible. If any of these measures cannot be found or a measure does not repre

Contact [7]

Answer:

1. Median = 10.1

2. A. The median represents the center.

3. D. The mode(s) can't represent the center because it (they) is(are) not a data value.

Step-by-step explanation:

Mean of a sample = sum of the samples/no of the samples

Samples in increasing order:

9.8

9.9

10.1

10.4

10.6

11.1

Mode is the sample with highest frequency.

Median is the middle entry of the data.

Mean = (9.8 + 9.8 + 9.9 + 10.1 + 10.4 + 10.6 + 11.1)/7

= 717/7

= 10.243

Median = 10.1

Mode = 9.8 because it has the highest frequency of 2

6 0

3 years ago

An isosceles trapezoid ABCD with height 2 units has all its vertices on the parabola y=a(x+1)(x−5). What is the value of a, if p

horrorfan [7]

Answer:

a = -0.3575

Step-by-step explanation:

The points A and D lie on the x-axis, this means that they are the x-intercepts of the parabola, and therefore we can find their location.

The points A and B are located where

$y=a(x+1)(x-5)=0$

This gives

$x=-1$

$y=5$

Now given the coordinates of A, we are in position to find the coordinates of the point B. Point B must have y coordinate of y=2 (because the base of the trapezoid is at y=0), and the x coordinate of B, looking at the figure, must be x coordinate of A plus horizontal distance between A and B, i.e

$B_x=A_x+\frac{2}{tan(60)} =-1+\frac{2\sqrt{3} }{3}$