Actual Distance =120 Km
We have to map 120 Km in the scale of 3 Cm.
i.e, 3 Cm = 120 Km
→ 1 cm = (120÷3) Km
→ 1 cm = 40 Km
So, if you scale 3 cm on the map correspond to 120 km,then
you have to scale , 1 Cm= 40 Km
Drawn the graph for you below.
Answer:
Decompose the figure into two rectangles and add the areas.
Step-by-step explanation:
We can draw a vertical line segment from the smaller section of the rectangle straight down. This would cut the rectangle into 2 smaller rectangles. We can then find the area of each rectangle and add them to find the area of the composite figure.
Answer:
1900
Step-by-step explanation:
hello bro how r u i think answer is 1835 but there is no option
<em><u>Answer: x=-2 *The answer should be the negative sign.*</u></em>
Step-by-step explanation:
distributive property: a(b+c)=ab+ac
remove parenthesis
-15x-15*4=-30
15*4=60
-15x-60=-30
add 60 both sides of an equation.
-15x-60+60=-30+60
simplify.
-15x=30
divide by -15 both sides of an equation.
-15x/-15=30/-15
simplify.
30/15=2
x=-2
Hope this helps!
Thanks!
Have a great day!
Answer:
y = 1/2x - 4
Step-by-step explanation:
If two lines are perpendicular to each other, they have opposite slopes.
The first line is y = -2x + 8. Its slope is -2. A line perpendicular to this one will have a slope of 1/2.
Plug this value (1/2) into your standard point-slope equation of y = mx + b.
y = 1/2x + b
To find b, we want to plug in a value that we know is on this line: in this case, it is (4, -2). Plug in the x and y values into the x and y of the standard equation.
-2 = 1/2(4) + b
To find b, multiply the slope and the input of x (4)
-2 = 2 + b
Now, subtract 2 from both sides to isolate b.
-4 = b
Plug this into your standard equation.
y = 1/2x - 4
This equation is perpendicular to your given equation (y = -2x + 8) and contains point (4, -2)
Hope this helps!
