A. You would start off by a rectangle in the middle, then you would place to squares on the bottom and top if the rectangle. After you've done that, you place two rectangles (Same size as the original) on both sides of the original rectangle. Finally you add a rectangle (Same size) to either ends of the secondary rectangles. It should look like this.
B. You would start off with a rectangle in the middle, then you would add 2 equilateral triangles to the top and bottom of the rectangle. After that, you Simply put 2 rectangles (Same size as the original) on both sides of the rectangle. It should look something like this.
C. To make a pyramid, it's actually quite simple. You would start off with a square in the middle, and then place equilateral triangles on ALL sides of the square. It should look something like this.
I hope this helped ^^
Step-by-step explanation:
a) f(4) = 7-2(4)
= -1
b) f(h) = 7-2(h)
= 7-2h
c) f(4) + f(h) = -1 +(7-2h)
= 6-2h
h = 3
d) f(3+h) = 7-2(3+h)
= 7-6-2h
= -1-2h
2h= -1
h = -1/2
p/s = if the real answer is different with my answer, tell me also please. Im just a student that still learning.
Answer:
24,150
Step-by-step explanation:
7% of 345,000 = 24,150
We know that
[lateral surface area of a regular triangular pyramid]=3*[area of one <span>equilateral triangle]
so
[area of one </span>equilateral triangle]=lateral surface/3-----> 81/3-----> 27 ft²
[<span>surface area of the regular triangular pyramid]=lateral area+area of the base
area of the base is equals to the area of the lateral sides because are </span>equilateral triangles
therefore
area of the base=27 ft²
[surface area of the regular triangular pyramid]=81+27----> 108 ft²
the answer is
<span>the surface area of the regular triangular pyramid is 108 ft</span>²
We are given the equation:
DA - 2qA = B³
Taking 'A' common on the LHS
A(D - 2q) = B³
Dividing both sides by (D - 2q)
A = B³ / (D - 2q)