What is the slope of a line that passes through (–4,–13) and (19,11)?
2 answers:
For points (x1,y1) and (x2,y2)
slope=(y1-y2)/(x1-x2)
(-4,-13)
(19,11)
x1=-4
y1=-13
x2=19
y2=11
slope=(-13-11)/(-4-19)=-24/-23=24/23
B is answer
B.
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