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sergejj [24]
3 years ago
7

Write the equation and then solve the equation

Mathematics
2 answers:
zalisa [80]3 years ago
7 0

Step-by-step explanation: I have attached the equation in the image provided.

Don't be intimidated by the fraction that appears on the left side of this equation. We start this problem by distributing or multiplying through the parentheses on both sides.

So as we distribute the 1/5 through the parentheses on the left side of the equation, we get 1/5 × y which is y/5 and 1/5 × -1 which is -1/5. On the right, let's change the -2 to + and negative 2 so we know that we're distributing a -2 through the parentheses. When we do that, the right side of the equation simplifies to 6 - 8 + 2y.

Now we have y/5 - 1/5 = 6 - 8 + 2y. Notice that we can go one step further with the right side of the equation as it simplifies to -2 + 2y.

Now we have y/5 - 1/5 = -2 + 2y.

Now we are ready to get rid of the fractions.

Since both fractions have a denominator of 5, we can get rid of the fractions by multiplying both sides of the equation by 5. Make sure you distribute the 5 through both terms on both sides of the equation.

On the left our 5's cancel and we're left with y - 1. On the right, 5 × -2 is -10 and 5 × 2y is 10y.

Now we have y - 1 = -10 + 10y.

From here, we add 1 to both sides of the equation and then we get the following equation. y = -9 + 10y

Now we subtract 10y from both sides of the equation and we get -9y = -9. From here, we divide both sides of the equation by -9 and we get y = 1.

In the image provided, I have only attached steps up to y - 1 = -10 + 10y but the rest of the work is explained above.

BabaBlast [244]3 years ago
5 0
X+1=1 find x

1. x=1-1
2. x=0

solved
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S=πrl+πr2 solve for l.
kipiarov [429]

Answer:

<h2>l =  \frac{s - π {r}^{2} }{πr}</h2>

Step-by-step explanation:

s = πrl + πr²

First move πr² to the left side of the equation

We have

πrl = s - πr²

Divide both sides by πr to make l stand alone

That's

<h3>\frac{\pi \:rl}{\pi \: r}  =  \frac{s - \pi \:  {r}^{2} }{\pi \: r}</h3>

We have the final answer as

<h3>l =  \frac{s - π {r}^{2} }{πr}</h3>

Hope this helps you

5 0
3 years ago
The variables y and x^2 are directly
choli [55]

Answer:

y = \frac{20}{21} x²

Step-by-step explanation:

Given that y and x² are directly proportional then the equation relating them is

y = kx² ← k is the constant of proportion

When x = 2

y = k × 2² = 4k

When x = 5

y = k × 5² = 25k

Then

25k - 4k = 20 ( difference between values is 20 )

21k = 20 ( divide both sides by 21 )

k = \frac{20}{21}

y = \frac{20}{21} x² ← equation of proportion

6 0
2 years ago
18 football teams who play each other twice. how many matches are played
tekilochka [14]

Answer:

Total number of matches = 306 matches

Step-by-step explanation:

Given:

Total number of team = 18

Per team number of play = 2

Find:

Total number of matches

Computation:

Total number of matches = [(Total number of team x 2)(Total number of team -1)]/2

Total number of matches = [(18 x 2)(18-1)]/2

Total number of matches = 612 / 2

Total number of matches = 306 matches

5 0
3 years ago
Maria studied the traffic trends in India. She found that the number of cars on the road increases by 10% each year. If there we
lord [1]

Answer:

b. 8,800,000.

Step-by-step explanation:

In maria study the number of cars on the road increases by 10% each year.

Total number of cars in the first year =80 million cars.

We will add 10% of 80 million to 80 milion to enable us get the number of cars for the second year.

For year 2 we have;

10% of 80,000,000+80,000,000

\frac{10}{100}*80,000,000+80,000,000

8,000,000 + 80,000,000

88,000,000

number of cars in year 2 = 88 million

We will add 10% of 88 million to 88 milion to enable us get the number of cars for the third year.

\frac{10}{100}*88,000,000+88,000,000

8,800,000+88,000,000

96,800,000

the number of cars on the road in year 3 compared to year 2 will just be the increase which is in BOLD. That is 8,800,000

<em>or simply subtract the number of cars in year 2 from that in year 3;</em>

96,800,000-88,000,000 = 8,800,000

8 0
3 years ago
Read 2 more answers
Which of the following have both 2 and -5 as solutions.
Stella [2.4K]
x_1=2;\ x_2=-5\\\\(x-2)(x-(-5))=(x-2)(x+5)=x^2+5x-2x-10=x^2+3x-10\\\\Answer:a.
3 0
3 years ago
Read 2 more answers
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