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4 years ago

Help Please!! I can't seem to get the answer no matter how hard I try.... But it seems so easy.. Wjhsjwskwnw

Mathematics

1 answer:

Gemiola [76]4 years ago

5 0

Answer:

109 cm³

Step-by-step explanation:

Let the radius of semi-circle be r, then side of the cube is 2r and the height of the solid is also 2r

<u>The circumference of the semi-circle can be calculated as:</u>

2r + 1/2 × (2πr) = 11

<u>Then we can find the value of r:</u>

r(2+π)=11
r= 11/(2+π)
r= 11/5.14
r= 2.14 cm

<u>The volume of the combined solid is the sum of volumes of the cube and the semi-cylinder:</u>

V= (2r)³ + 1/2×πr²×2r= 8r³ + πr³= (8+π)×r³

V= (8+3.14)×2.14³ = 109.1758 cm³

<h2>The volume is approx. 109 cm³</h2>

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Of all customers purchasing automatic garage-door openers, 75% purchase Swedish model. Let X = the number among the next 15 purc

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Answer:

$P(X=k) = {15 \choose k} * 0.75^{k}*0.25^{15-k}$

For any integer k between 0 and 15, and 0 for other values of k.

$P(X>10) = 0.2252+ 0.2252+ 0.1559+0.0668+0.0134 = 0.6865$

c) P(6 ≤ X ≤ 10) = 0.2737

d) μ = 15*0.75 = 11.25. σ² = 11.25*0.25 = 2.8125

Step-by-step explanation:

X is a binomial random variable with parameters n = 15, p = 0.75. Therefore

$P(X=k) = {15 \choose k} * 0.75^{k}*0.25^{15-k}$

For any integer k between 0 and 15, and 0 for other values of k.

P(X>10) = P(X=11) + P(X=12)+ P(X=13)+P(X=14)+P(x=15)

$P(X=11) = {15 \choose 11} * 0.75^{11} * 0.25^4 = 0.2252$

$P(X=12) = {15 \choose 12} * 0.75^{12} * 0.25^3 = 0.2252$

$P(X=13) = {15 \choose 13} * 0.75^{13} * 0.25^2 = 0.1559$

$P(X=14) = {15 \choose 14} * 0.75^{14} * 0.25 = 0.0668$

$P(X=15) = {15 \choose 15} * 0.75^{15} = 0.0134$

Thus,

$P(X>10) = 0.2252+ 0.2252+ 0.1559+0.0668+0.0134 = 0.6865$

c) P(6 ≤ X ≤ 10) = P(X = 6) + P(X = 7) + P(X = 8) + P(X=9) + P(X=10)

$P(X=6) = {15 \choose 6} * 0.75^{6} * 0.25^9 = 0.0034$

$P(X=7) = {15 \choose 7} * 0.75^{7} * 0.25^8 = 0.0131$

$P(X=8) = {15 \choose 8} * 0.75^{8} * 0.25^7 = 0.0393$

$P(X=9) = {15 \choose 9} * 0.75^{9} * 0.25^6 = 0.0918$

$P(X=10) = {15 \choose 10} * 0.75^{10} * 0.25^{5} = 0.1652$

Thereofre,

$P(6 \leq X \leq 10) = 0.0034 + 0.0134 + 0.0393 + 0.0918 + 0.1652 = 0.2737$

d) μ = n*p = 15*0.75 = 11.25

σ² = np(1-p) = 11.25*0.25 = 2.8125

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Help Please!! I can't seem to get the answer no matter how hard I try.... But it seems so easy.. Wjhsjwskwnw​

Help Please!! I can't seem to get the answer no matter how hard I try.... But it seems so easy.. Wjhsjwskwnw