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inysia [295]
2 years ago
9

HELP ME PASS!!!! YOULL BE MY HERO FOREVER!!!!!!

Mathematics
2 answers:
Alexus [3.1K]2 years ago
4 0

2(-2y-4)-3y=13

-4y-8-3y=13

-7y=21

y=-3

x=2

substitute three into one of the original two problems and you get 2!

Hope this helped

marishachu [46]2 years ago
4 0

Answer:

all work is shown and pictured

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Help plz! Will mark as brainiest JUST HELP PLZ
Volgvan

1) The lengths of the other 2 sides are 51 feet.

Isosceles triangles have at least 2 equal sides. The base is 60 feet, so we can assume that the other 2 sides are equal

162 = 60 + 2x

x = the equal sides of the triangle.

162 - 60 = 102

102 = 2x

Divided by 2

51 = x

51 + 51 = 102. 102 + 60 = 162

2)

Pool 1: 311.38ft.

8*19.4 = 155.2

8 * 5.7 * 2 = 91.2

5.7 * 5.7 = 32.49/2 (because its a triangle) = 16.254*4 = 64.98

155.2 + 91.2 + 64.98 = 311.39

Pool 2: Either 863.94ft or 484 + 121πft

22 * 22 = 484

22/2 = 11, So, the radius of the half circle is 11

Circle area = (pi)r^2

11*11 = 121

pi * 121 = 121pi

Using 3.14 substitute: 3.14 * 121 = 379.94

379.94 + 484 = 863.94

Pool 3: 207ft

Rhombus area = pq/2

18 * 12 = 216

216/2 = 108

11 * 18 = 198/2 = 99

99 + 108 = 207

7 0
2 years ago
Would each of them be able to be the side lengths of a triangle?
ratelena [41]
Pythagoras Theorem:
hipotenuse²=leg₁²+leg₂²

First posible triangle:
hypotenuse=13    (13²=169)
leg₁=12                ( 12²=144)
leg₂=5                  (5²=25)

13³=144 + 25


Answer:can be side lengths of a triangle

Second triangle:
 hypotenuse=12.6    (12.6²=158.76)
leg₁=6.7                ( 6.7²=44.89)
leg₂=6.5                  (6.5²=42.25)

leg₁²+leg₂²=44.89+42.25=87.14≠158.76

Answer: cannot be side lenghts of a triangle.

third triangle:
hypotenuse=13    (13²=169)
leg₁=12                ( 12²=144)
leg₂=11                  (11²=121)

leg₁²+leg₂²=144+121=265≠169

Answer: cannot be side lenghts of a triangle.

fourth triangle:
hypotenuse=13   (13²=169)
leg₁=6                ( 6²=36)
leg₂=4                  (4²=16)

leg₁²+leg₁²=36+16=52≠169

Answer: cannot be side lenghts of a triangle.
8 0
3 years ago
Read 2 more answers
Which procedure justifies whether Negative 3 x (5 minus 4) + 3 (x minus 6) is equivalent to Negative 12 x minus 6? The expressio
Nady [450]

Answer:

The expressions are not equivalent because -3(2)(5-4)+3(2-6)=-18 and -12(2)-6=-30

Step-by-step explanation:

Two expressions are said to be equal if after a number is substituted to the expression, they produce the same result (that is they have the same value).

To determine whether -3x(5-4)+3(x-6) is equivalent to -12x-6, we have to substitute the same number to the expression and see if it produces the same result.

Substituting 2 to the first expression gives:

-3×2(5-4) + 3(2 - 6) = -6 - 12 = -18

Substituting 2 to the second expression gives:

-12(2) - 6 = -24 - 6 = -30

Since -3×2(5-4) + 3(2 - 6) = -6 - 12 = -18 and -12(2) - 6 = -24 - 6 = -30, the expressions are not equivalent because they do not produce the same result.

7 0
3 years ago
Read 2 more answers
The secret number has a 7 in the ones place. The tens number is an odd number
Lana71 [14]
This really is left up to you as long as you have an odd number in the tens place and a 7 in the ones place. How big (or small) the number is is up to you. As long as it is at least 17, it's pretty much up to you.
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2 years ago
The midpoint of ST is M=(-2.1). One endpoint is S=(-6. -4).
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3 years ago
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