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4 years ago

Triangle ABC has vertices at A(2, 2), B(4,7), and C(6,2). Classify the triangle according to the side lengths.

Mathematics

1 answer:

zmey [24]4 years ago

4 0

Answer:

Isosceles triangle

Step-by-step explanation:

Length AB

√(4 - 2)² + (7 - 2)²

√2² + 5²

√4 + 25

√29

Length AC

6 - 2 = 4

Length BC

√(6 - 4)² + (2 - 7)²

√2² + (-5)²

√4 + 25

√29

Length AB and BC is the same.

Length AC is the longest side.

Therefore, it is an isosceles triangle.

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4. Lucy is k years old. She has a sister who is three years younger than she is and

WITCHER [35]

Answer:

4k - 8

Step-by-step explanation:

Lucy is k years old so we know k is an important part of this problem.
Sister 1 is 3 years younger, so she is k - 3 years old.
Sister 2 is 5 years less than twice Lucy's age therefore, she is 2k (twice Lucy's age) - 5 years old.
Now we have: k + (k - 3) + (2k - 5)
We can simplify like terms with the k's and get 4k. then we add (-3) and (-5) to get 4k - 8.

Hope this helps!

7 0

3 years ago

What is the scientific notation 0.91?

sweet-ann [11.9K]

Answer:

The scientific notation of 0.91 is: 9.1 × 10-1

Step-by-step explanation:

5 0

4 years ago

Read 2 more answers

5. Change 518in squared to ft. Squared. Round to the nearest tenth.

anzhelika [568]

9514 1404 393

Answer:

3.6

Step-by-step explanation:

There are 144 in² in 1 ft².

(518 in²) × (1 ft²)/(144 in²) ≈ 3.597222... ft² ≈ 3.6 ft²

5 0

3 years ago

Calculate the range, population variance, and population standard deviation for the following data set. If necessary, round to o

Roman55 [17]

Answer:

$Range = 11-2=9$

$\mu = \frac{2+3+4+5+6+7+8+9+10+11}{10}=6.5$

$\sigma^2 =8.25 \approx 8.3$

$\sigma = \sqrt{8.25}= 2.87 \approx 2.9$

Step-by-step explanation:

Assuming this question: "Calculate the range, population variance, and population standard deviation for the following data set. If necessary, round to one more decimal place than the largest number of decimal places given in the data. 2,3,4,5,6,7,8,9,10,11 "

Solution to the problem

The range is defined as $Range = Max -Min$ and if we replace we got:

$Range = 11-2=9$

Now we can calculate the population mean with this formula:

$\mu =\frac{\sum_{i=1}^n X_i}{N}$

And if we replace we got:

$\mu = \frac{2+3+4+5+6+7+8+9+10+11}{10}=6.5$

The population variance is given by:

$\sigma^2 = \frac{\sum_{i=1}^n (X_i -\mu)^2}{N}$

And after replace we got: $\sigma^2 =8.25 \approx 8.3$

And the population standard deviation would be just the square root of the variance and we got:

$\sigma = \sqrt{8.25}= 2.87 \approx 2.9$

4 0

4 years ago

Can someone help me or is this website a waste of time

Ludmilka [50]

Answer:

Step-by-step explanation:lol what do u need help on

3 0

3 years ago