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fomenos
3 years ago
9

The area of rectangular Envelope is given by the trinomial x^2 +8x+7. The length of the envelope is x+7. What is the width of th

e envelope ?
Mathematics
1 answer:
stealth61 [152]3 years ago
7 0
X+1 is the width of the envelope. If you need work just say do in the comments please.
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diamong [38]

Answer:

28

Step-by-step explanation:

You times 8/3 and 21/2 to get 28

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Step-by-step explanation:

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What is the value of X?
rodikova [14]

Answer:

102

Step-by-step explanation:

triangle area = 180 degrees

straight line = 180 degrees

180 - 127 = 53

49

49 + 53 + 3rd angle = 180

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3 years ago
Please help within 5 minutes!!
inn [45]

Answer:

F

Step-by-step explanation:

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3 years ago
Yoonie is a personnel manager in a large corporation. Each month she must review 16 of the employees. From past experience, she
Anarel [89]

Answer:

P(3.25 < \bar X < 4.25)

And we can use the z score formula given by:

z = \frac{\bar X -\mu}{\sigma_{\bar X}}

And using the z score we have:

P(\frac{3.5-4}{0.3}< Z< \frac{4.25-4}{0.3}) = P(-1.667< Z< 0.833)

And we can use the normal standard distribution table or excel in order to find the probabilities and we got:

P(-1.667< Z< 0.833)= P(Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the time it takes her to complete one review, and for this case we know the distribution for X is given by:

X \sim N(4,1.2)  

Where \mu=4 and \sigma=1.2

And we select a sample size of n =16. Since the dsitribution for X is normal then the distribution for the sample mean \bar X is also normal and given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\sigma_{\bar X}= \frac{1.2}{\sqrt{16}}= 0.3

For this case we want to find this probability:

P(3.25 < \bar X < 4.25)

And we can use the z score formula given by:

z = \frac{\bar X -\mu}{\sigma_{\bar X}}

And using the z score we have:

P(\frac{3.5-4}{0.3}< Z< \frac{4.25-4}{0.3}) = P(-1.667< Z< 0.833)

And we can use the normal standard distribution table or excel in order to find the probabilities and we got:

P(-1.667< Z< 0.833)= P(Z

The graph illustrating the problem is on the figure attached.

4 0
3 years ago
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