Answer:the weight after 225 days is
22885 kilograms
Step-by-step explanation:
The initial weight of the blue whale calf at birth is 2725 kilograms. blue whale calf gains 90 kilograms of weight each day for the first 240 days after its birth. The weight increases in arithmetic progression. This means that the first term of the sequence, a is 2725, the common difference, d is 90.
The formula for the nth term of an arithmetic sequence is expressed as
Tn = a + (n - 1)d
Where
n is the number of terms of the sequence.
a is the first term
d is the common difference
We want to determine its weight, T225 after 225 days after it’s birth. It means that n = 225
Therefore
T225 = 2725 + (225 - 1)90
T225 = 2725 + 224×90 = 2725 + 20160
T225 = 22885
Answer:
149
Step-by-step explanation:
If you order the numbers from smallest to biggest and then find the middle number it is 149
Answer:
The country's population for the year 2030 is 368.8 million.
Step-by-step explanation:
The differential equation is:
Integrate the differential equation to determine the equation of P in terms of <em>t</em> as follows:
![\int\limits {\frac{1}{P(600-P)} } \, dP =k\int\limits {1} \, dt \\(\frac{1}{600} )[(\int\limits {\frac{1}{P} } \, dP) - (\int\limits {\frac{}{600-P} } \, dP)]=k\int\limits {1} \, dt\\\ln P-\ln (600-P)=600kt+C\\\ln (\frac{P}{600-P} )=600kt+C\\\frac{P}{600-P} = Ce^{600kt}](https://tex.z-dn.net/?f=%5Cint%5Climits%20%7B%5Cfrac%7B1%7D%7BP%28600-P%29%7D%20%7D%20%5C%2C%20dP%20%3Dk%5Cint%5Climits%20%7B1%7D%20%5C%2C%20dt%20%5C%5C%28%5Cfrac%7B1%7D%7B600%7D%20%29%5B%28%5Cint%5Climits%20%7B%5Cfrac%7B1%7D%7BP%7D%20%7D%20%5C%2C%20dP%29%20-%20%28%5Cint%5Climits%20%7B%5Cfrac%7B%7D%7B600-P%7D%20%7D%20%5C%2C%20dP%29%5D%3Dk%5Cint%5Climits%20%7B1%7D%20%5C%2C%20dt%5C%5C%5Cln%20P-%5Cln%20%28600-P%29%3D600kt%2BC%5C%5C%5Cln%20%28%5Cfrac%7BP%7D%7B600-P%7D%20%29%3D600kt%2BC%5C%5C%5Cfrac%7BP%7D%7B600-P%7D%20%3D%20Ce%5E%7B600kt%7D)
At <em>t</em> = 0 the value of <em>P</em> is 300 million.
Determine the value of constant C as follows:
It is provided that the population growth rate is 1 million per year.
Then for the year 1961, the population is: P (1) = 301
Then 
.
Determine <em>k</em> as follows:
For the year 2030, P (2030) = P (70).
Determine the value of P (70) as follows:
Thus, the country's population for the year 2030 is 368.8 million.
Answer:
2
Step-by-step explanation:
here is how to do it 13/6=2
The answer is Graph D because it drops then it goes back up
