Factorise the following expressions 5x^2-25xy

The price p of a gallon of gas goes up to $0.05 cents on Friday. On Saturday the price goes down $0.03. Write a expression with

m_a_m_a [10]

Answer:

The expression with three terms to show the price of a gallon of gas on Saturday is ⇒ $p+0.05-0.03$

Step-by-step explanation:

Given:

Price of a gallon of gas in dollars = $p$

On Friday, the price goes up by = $0.05

On Saturday, the price goes down by = $0.03

To write an expression with three terms to show the price of a gallon of gas on Saturday.

Solution:

Initial price of a gallon given in dollars was = $p$

On Friday the price increased by $0.05.

So, the price on Friday in dollars can be given as = $p+0.05$

On Saturday, the price decreased by $0.03

So, the price on Saturday in dollars can be given as = $p+0.05-0.03$

Thus, the expression with three terms to show the price of a gallon of gas on Saturday is ⇒ $p+0.05-0.03$

4 0

3 years ago

PLLLZZ HHEELLPPP! QUESTION IS BELOW!

Lubov Fominskaja [6]

Answer:

32°

Step-by-step explanation:

The two given angles are complementary, it means they add to 90°

2x + 10 + x + 8 = 90
3x + 18 = 90
3x = 72
x = 24

m∠Y = x + 8 = 24 + 8 = 32°

3 0

3 years ago

Electric current flowing through wire produces heat that

morpeh [17]

I’m not sure? But don’t answer the guy with the bitly it’s a scam

5 0

3 years ago

In a journey of 15 miles, two third distance was travelled with 40 mph and remaining with 60 mph. How much time does the journey

Ad libitum [116K]

The first step in solving this question is to split the journey into 2 parts. In the first part of the journey, $\frac{2}{3} \times 15 = 10$ miles are covered at a speed of 40 mph. In the second part the journey 5 miles are covered at a speed of 60 mph.

The equation to compute the time of a journey given the speed and distance is $t=\frac{d}{s}$ where $t$ is the time, $s$ is the speed and $d$ is the distance.

The time for the first part of the journey is calculated as shown below,

$t=\frac{d}{t} \\t=\frac{10m}{40mph} =\frac{10}{40} h$ .

The time for the second part of the journey is calculated as follows,

$t=\frac{d}{t} \\t=\frac{5m}{60mph} =\frac{5}{60} h$ .

The total time is the sum of the times taken to cover each part of the journey and is calculated as shown below,

$t=\frac{10}{40} h+\frac{5}{60} =\frac{30+10}{120} h=\frac{40}{120}h =\frac{1}{3} h$

The time to cover the journey is a third of an hour or 20 minutes.

5 0

3 years ago

A number was written on the board. one student increased the number by 23, but another student decreased the number by 1. the fi

Softa [21]

Let the number be x.

First student increased the number by 23, therefore
⇒ x + 23

Second student decreased the number by 1, therefore
⇒ x - 1

The first student's result was 7 times greater than the result of the second student's, therefore
⇒ x + 23 = 7(x - 1)

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Solve for x:
----------------------------------------------
x + 23 = 7( x- 1)
x + 23 = 7x - 7
6x = 30
x = 5

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Answer: The number on the board is 5.
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4 0

4 years ago

Read 2 more answers

Factorise the following expressions 5x^2-25xy​

Factorise the following expressions 5x^2-25xy