The GCF of 180 and 240 is 60
You simply put 40 over a hundred and 55 over n (which is the number were trying to find) so you do cross multiplication. 55 times a hundred and after you get the answer. You divide it by 40 and should get 137.5.
The question is incomplete. Here is the complete question:
Mr.yueng graded his students math quizzes students came up with four different answers when solving the equation x3=22. Which answers is correct.
(A) 
(B) ![\sqrt[3]{22}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B22%7D%20)
(C)
(D) 
Answer:
(B) ![\sqrt[3]{22}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B22%7D)
Step-by-step explanation:
Given:
The equation to solve is given as:

Here, the left hand side of the equation has a variable 'x' in exponent form. So, in order to solve for 'x', we have to eliminate the exponent.
For removing the exponent, we have to take cubic root on both the sides. As we know that,
![\sqrt[n]{x^n} =x](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5En%7D%20%3Dx)
So, taking cubic root on both the sides, we get
![\sqrt[3]{x^3}=\sqrt[3]{22}\\\\x=\sqrt[3]{22}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E3%7D%3D%5Csqrt%5B3%5D%7B22%7D%5C%5C%5C%5Cx%3D%5Csqrt%5B3%5D%7B22%7D)
Therefore, the second student has written the correct answer and hence the correct option is (B).
Answer:
2
Step-by-step explanation:
Given the data : 29, 2, 28, 30, 26, 31
Outlier ;
Lower :Q1 - (1.5 * IQR)
Upper : Q3 + (1.5 * IQR)
Q1 = Lower quartile ; Q3 = upper quartile ; IQR = Interquartile range
Using calculator :
Q1 = 26
Q3 = 30
IQR = (Q3 - Q1) = 30 - 26 = 4
Lower : 26 - (1.5 * 4) = 20
Upper : 30 + (1.5 * 4) = 36
Hence, the number in the given data which falls outside the range is 2
3x(x+3)^2
3x(x^2 + 6x + 9)
= 3x^3 + 18x^2 + 27x
answer
3x^3 + 18x^2 + 27x