Third grade homework 1.3 rounding to the nearest
2 answers:
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Answer:
23) No
24) No
25) Yes
Step-by-step explanation:
Question 23)
We want to determine if a zero exists between 1 and 2 for the function:
Find the zeros of the function. We can factor:
Zero Product Property:
Solve for each case. Hence:
Therefore, our zeros are at <em>x</em> = 5 and <em>x</em> = -1.
In conclusion, a zero does not exist between 1 and 2.
Question 24)
We have the function:
And we want to determine if a zero exists between 1 and 2.
Factor. We want to find two numbers that multiply to (2)(3) = 6 and that add to -7.
-6 and -1 suffice. Hence:
By the Zero Product Property:
Solve for each case:
Therefore, our zeros are at <em>x </em>= 1/2 and <em>x</em> = 3.
In conclusion, a zero does not exist between 1 and 2.
Question 25)
We have the function:
And we want to determine if a zero exists between -2 and 3.
Factor. Again, we want to find two numbers that multiply to 3(-5) = -15 and that add to -2.
-5 and 3 works perfectly. Hence:
By the Zero Product Property:
Solve for each case:
In conclusion, there indeed exists a zero between -2 and 3.