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Vilka [71]
3 years ago
10

a wrestler is weighing in for their match this evening. their normal weight is 168 pounds, but that weight can vary by as much a

s 3.2 pounds. write an equation that models this situation and find their minimum and maximum weight.
Mathematics
1 answer:
Natalija [7]3 years ago
5 0

<em>Introduction </em>

<em>Wrestling is a wonderful activity with many advantages for the student-athlete. It is a sport that is highly </em>

<em>competitive, exciting and satisfying. It is a sport that provides for individual and team competition. It is - </em>

<em>and should be - fun. Unfortunately, the practice of losing weight by not eating, restricting fluid intake and </em>

<em>over-exercising reduces the sport's fun. This information is presented to help clear up misconceptions </em>

<em>regarding wrestling and weight loss. I also hope to give some guidance to those who desire to manage </em>

<em>their weight properly in preparation for and during the wrestling season. </em>

<em>History and Stigma </em>

<em>For too long, the wrestling community has unthinkingly accepted the myth that to be a good wrestler, you </em>

<em>must cut weight. The generally accepted thinking is something like this: if your natural weight is 135 </em>

<em>pounds, you may be a good wrestler at 135 pounds. But if you wrestle at 130 pounds, you'll be a better </em>

<em>wrestler. And if you can make it down to 125, you'll be a state champion. No facts support that widely held </em>

<em>view, yet wrestlers and parents subscribe to that faulty reasoning. Looking further back, many remember </em>

<em>the days that losing excessive weight was a specific practice and expectation among wrestlers. It was </em>

<em>supposed to teach sacrifice, commitment, and the idea of “No Pain, No Gain.” </em>

<em>Regardless of the current attitude of the majority of the wrestling community, the stigma that an unhealthy </em>

<em>loss of weight is a requirement of wrestling among outside observers sticks. The Virginia High School </em>

<em>League has followed national guidelines to establish rules that encourage healthy weight management </em>

<em>among wrestlers. </em>

<em>Current Regulations </em>

<em>Preseason weight certification is accomplished with three steps. The first is determining each wrestler’s </em>

<em>body fat percentage using skin fold calipers. Next, the wrestler completes a hydration test, to insure </em>

<em>against a dehydrated weight measurement, and the wrestler weighs in. The third step is the calculation of </em>

<em>the wrestler’s minimum wrestling weight based on 7% body fat for males and 12% for females. The </em>

<em>wrestler may not wrestle at a weight class below his minimum weight during the season. The wrestler is </em>

<em>also restricted from losing more then 1.5% body weight loss per week (official weigh-ins at certification, </em>

<em>matches, and tournaments are used for this calculation). A one-pound per month growth allowance is </em>

<em>provided to allow for the natural growth of this age group. The VHSL advises, and we have instituted, </em>

<em>daily weigh-ins before and after practice to monitor weight-loss and dehydration. </em>

<em>Additionally, the National Federation of State High School Associations has adopted several other rules to </em>

<em>guide coaches and wrestlers while managing their weight. Wrestlers are discouraged from wrestling at a </em>

<em>weight class more then one weight class above their certified weight. </em>

You might be interested in
PLEASE HELP-
Deffense [45]

Answer:

1492.88

Step-by-step explanation:

V = πr^2 h/3

3.14 × 18^2

3.14 × 324 = 1017.36

1017.36 × 4.4 = 4476.384

4476.384 ÷ 3 = 1492.88

Hope this helped.

5 0
3 years ago
Kendra has a math test every 12 school days and a vocabulary test every 9 school days.She had both a math and a vocabulary test
Hunter-Best [27]
36 days

9*4 = 36
12*3 = 36
8 0
3 years ago
The circumference is 1 mile. What is the diameter?
iren2701 [21]

Answer:

Step-by-step explanation:

circumference  = 2* pi * radius = 1

-> radius = 0.1592 mile

-

> diameter = 2* radius = 0.31847 mile

8 0
3 years ago
What is the nearest thousand place for 3,429
muminat
If the place to the right of where you are rounding is 5 or higher, you have to round up. If it is 4 or lower, you have to round down. In the hundreds place, there is a 4. That's lower than 5 meaning that you round down/stay. So, the nearest thousands place is 3,000.
8 0
3 years ago
Can someone please help me with this question?
liq [111]
To get the solution we are looking for we need to point out what we know.
1. We assume that 55 is 100% because its the output value of the task.
2. We assume that the x is the value we are looking for. 
3. If 100% = 55 so we can write it down as 100%=55 
4. We know that x% = 44 of the output value so we can write it as x%=44.
5. Now we have two simple equations: 1) 100%=55 2) x%=44 where left sides of both of them have the same units and both right sides have the same units so we can do something like that 100%/x%=55/44.
6. Now we just have to solve the simple equation and we will get the answer.
7. Solution for 44 is what percent of 55 100%/x%=55/44 (100/x)*x=(55/44)*x we multiply both sides of the equation by x 100= 1.25*x we divide both sides of the equation by (1.25) to get x 100/1.25=x 80=x now we have: 44 is 80% of 55! 

Quick answer = 44 is 80% of 55
Hope this helps! ;D
3 0
3 years ago
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