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Masja [62]
3 years ago
15

How much coffee costing $4 a pound should be mixed with 3 pounds of coffee costing 4.50 a pound to obtain a mixture costing $4.3

0 a pound
Mathematics
1 answer:
Aleks04 [339]3 years ago
3 0

Answer:

The quantity of coffee costing $4 a pound in the coffee mixture is 2 pounds.

Step-by-step explanation:

Given: Coffee costing $4 a pound is mixed with 3 pounds of coffee costing 4.50 a pound to obtain a mixture costing $4.30 a pound.

We have to find the quantity of coffee costing $4 a pound in the mixture.

Let x represent the number of pounds of $4 coffee.

Cost of one pound = 4x.

Cost of  3 pounds of coffee costing 4.50 a pound = 3(4.50)

Cost of mixture costing $4.30 a pound = (x+3)(4.30)

According to given problem,

4x+3(4.50)=(x+3)4.30

Solving for x, we get,

\Rightarrow 4x+13.5=4.30x+12.9

Rearranging like term together, we get,

\Rightarrow 13.5-12.9=4.30x-4x

\Rightarrow 0.6=0.30x

\Rightarrow x=2

Thus, the quantity of coffee costing $4 a pound in the coffee mixture is 2 pounds.

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Austin purchase 2/3 of a pound of yum yum treats. If yum yum treats are $6.00 per pound how much does Austin pay
Oksi-84 [34.3K]
1. The information given in the problem above, is:

 - Austin purchases <span>2/3 of a pound of yum yum treats.
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 2. Keeping this on mind you have: If 1 pound of </span>yum yum treats is $6.00, how much is 2/3 of a pound?

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3 years ago
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Gala2k [10]

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Step-by-step explanation:

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Step-by-step explanation:

there you go

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