Which ordered pair is a solution to this equation? 5x - 10y = 35 (7, 1) (1, -3) (8, -4) (-2, 6)

How much time is it from 3:45pm to 5:15pm

Leokris [45]

1 hour and 30 minutes because when you subtract those you will get that answer

4 0

3 years ago

Read 2 more answers

The equation 6y = 30 - 8x has solutions of (b, 1) and (a, b). What are the values of a and b?

victus00 [196]

The values of $a$ and $b$ are $a = \frac{3}{2}$ and $b = 3$ , respectively.

In this question we need to solve the linear equation for each point, first for $(x,y) = (b, 1)$ and later for $(x,y) = (a, b)$ .

If we know that $(x,y) = (b, 1)$ , then the value of $b$ is:

$6 = 30-8\cdot b$

$8\cdot b = 24$

$b = 3$

If we know that $(x,y) = (a, b)$ and $b = 3$ , then the value of $a$ is:

$6\cdot b = 30 - 8\cdot a$

$18 = 30-8\cdot a$

$12 = 8\cdot a$

$a = \frac{3}{2}$

The values of $a$ and $b$ are $a = \frac{3}{2}$ and $b = 3$ , respectively.

To learn more on linear functions, we kindly invite to check this question: brainly.com/question/5101300

6 0

2 years ago

National data indicates that 35% of households own a desktop computer. In a random sample of 570 households, 40% owned a deskt

Elan Coil [88]

Answer:

Yes, this provide enough evidence to show a difference in the proportion of households that own a desktop.

Step-by-step explanation:

We are given that National data indicates that 35% of households own a desktop computer.

In a random sample of 570 households, 40% owned a desktop computer.

Let p = population proportion of households who own a desktop computer

SO, Null Hypothesis, $H_0$ : p = 25% {means that 35% of households own a desktop computer}

Alternate Hypothesis, $H_A$ : p $\neq$ 25% {means that % of households who own a desktop computer is different from 35%}

The test statistics that will be used here is One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of 570 households who owned a desktop computer = 40%

n = sample of households = 570

So, test statistics = $\frac{0.40-0.35}{{\sqrt{\frac{0.40(1-0.40)}{570} } } } }$

= 2.437

Since, in the question we are not given with the level of significance at which to test out hypothesis so we assume it to be 5%. Now at 5% significance level, the z table gives critical values of -1.96 and 1.96 for two-tailed test. Since our test statistics doesn't lies within the range of critical values of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that % of households who own a desktop computer is different from 35%.

3 0

3 years ago

Necesito las respuestas

Stels [109]

Answer:

I need it in English please so I can helps

3 0

2 years ago

Which table corresponds to the graph above?

Mumz [18]

There isn’t a graph shown

8 0

2 years ago