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qaws [65]
3 years ago
11

Which ordered pair is a solution to this equation? 5x - 10y = 35 (7, 1) (1, -3) (8, -4) (-2, 6)

Mathematics
1 answer:
Nataly_w [17]3 years ago
7 0
(1,-3) is the anwser
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Which choices are equivalent to the expression below check all that apply √-25 <br><br> please help.
nadezda [96]
B and D
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7 0
3 years ago
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5/4 as a mixed fraction
neonofarm [45]

Answer:

1 1/4 is your answer.

Step-by-step explanation:

What you do is you divide.

4 goes into 5 1 time with 1 left over.

1 1/4 is your answer.

3 0
3 years ago
X - 8 ≤ 4 or 2x + 3 &gt; 9<br> step by step pls
Alchen [17]

Answer:

x - 8 ≤ 4

  +8    +8                         Add eight to both sides of the equation.

X≤12

2x + 3 > 9

     -3     -3                        Subtract three from both sides

2x>6                                  Divide both sides by 2

x>3

Hope this helps!

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3 0
3 years ago
At the playground, 60% of the bike rack was filled. Thisis 30 bikes. How many total slots are there for bicycles?
Blizzard [7]
The most simplest way to explain this is by breaking down the 60%.

Think about it.

If 60% space = 30 bikes

then 30% space = 15 bikes

then 10% space must be 5 bikes.

So we now know for sure 60% space = 30 bikes.
And 10% space = 5 bikes.

Then we know remaining 40% space = 20 bikes.

So total space = 100% space, for 50 bikes.

7 0
4 years ago
a square field has a side 150 m long .There is a road 5 m wide all around the park outside it .Find the cost of constructing the
alisha [4.7K]

Answer:

Cost to construct the road = 775000 rupees

Step-by-step explanation:

Square field has a side = 150 m

Area of the field = (Side)²

                           = (150)²

                           = 22500 m²

Length of the park with road around the field = 150 + 2×(width of the road)

                                                                            = 150 + (2×5)

                                                                            = 160 m

Similarly, width of the park with road around the field = 160 m

Area of the park with road = (Side)²

                                            = (160)²

                                            = 25600 m²

Area of road = Area of the park with road - Area of the park

                     = 25600 - 22500

                     = 3100 m²

Since, cost of constructing the road = 250 rupees per square meter

Cost to construct the road with the given area = 250 × 3100

                                                                              = 775000 rupees

6 0
3 years ago
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