Answer:
No
Step-by-step explanation:
The answer is no because no pocket can be empty and there isn't enough money to satisfy the condition. At least, one dollar must be stored in each pocket but the number (integer) of dollars in each pocket is different.
Let's store the minimum amount of dollars in the pockets while satisfying the condition. Place 1 dollar in the first pocket. The second pocket must have 2 dollars (it can't be 1 dollar, it must be a different number of dollars). The third pocket must have third dollars.
Repeating this process, the ninth pocket must have 9 dollars. At this moment, we have arranged 1+2+3+4+5+6+7+8+9=45 dollars in our pockets. But we only had 44 dollars! Plus, the tenth pocket is still empty.
If you store more dollars on the first, second, nth pockets, you will just run out of money more quickly than in our process above. so it's impossible to arrange the money in such way.
<u><em>Tell Me If Somethings wrong with my answer! </em></u>
If you mean find the one that has the number 1 on it your answer is 13.
90+77+x=180
167+x=180
X=13
They is 9dime and 13 Nickels because 13 x5=65 and 9 x10=90 .So 0.65+ 0.90= 1.55.
Answer:
23:600
24
a12
b27
c36
d45
Step-by-step explanation:
