Answer:
There is a 0.82% probability that a line width is greater than 0.62 micrometer.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.
In this problem
The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so
.
What is the probability that a line width is greater than 0.62 micrometer?
That is 
So



Z = 2.4 has a pvalue of 0.99180.
This means that P(X \leq 0.62) = 0.99180.
We also have that


There is a 0.82% probability that a line width is greater than 0.62 micrometer.
Answer: centimeter
Step-by-step explanation:
Answer:
Similar, AA similarity, ΔAKL
Step-by-step explanation:
BC and KL are parallel. Therefore, ∠B and ∠K are alternate interior angles, and ∠C and ∠L are also alternate interior angles. Alternate interior angle are congruent, so by AA similarity, ΔABC ~ ΔAKL.
Answer:
The answers are as follows for the functions.
f(1) = 12
f(3) = 22
f(5) = 32
Step-by-step explanation:
To find any of these, simply input the value in for x in the equation given.
f(1)
f(x) = 5x + 7
f(x) = 5(1) + 7
f(x) = 5 + 7
f(x) = 12
You can repeat this for each of them and it will allow you to use all of the numbers in the equations given.
Answer:
the answer is (2,-3)
Step-by-step,-explanation: