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Yuri [45]
3 years ago
12

Henry buys 6 circus tickets for himself and five friends for a total of $174. Each friend pays Henry back for his or her ticket.

If one of Henry's friends gives him two $20 bills, how much change should Henry return?
Mathematics
1 answer:
Deffense [45]3 years ago
5 0

Answer:

$11

Step-by-step explanation:

According to the statement, you have that 6 tickets for the price of each ticket is equal to $174 and from that, you can determine the price of each ticket:

6*P=174

P= price of each ticket

P= 174/6= 29

Now, as it says that one of Henry's friends gives him two $20 bills, that means that he gives him $40 and you have to subtract the price of the ticket from that:

40-29= 11

The answer is that if one of Henry's friends gives him two $20 bills, Henry has to return $11.

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allochka39001 [22]

Hey there!

They are both correct, and their expressions are equivalent.'

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8 0
3 years ago
Find the quotient of <br><br> -85^2-27n+76 / -17n-19
bagirrra123 [75]
<u><em>Answer:</em></u>
5n-4

<u><em>Explanation:</em></u>
<u>The given expression is:</u>
\frac{-85n^2-27n+76}{-17n-19}

<u>1- Take the negative as a common factor from both the numerator and the denominator. This will give us:</u>
\frac{-(85n^2+27n-76)}{-(17n+19)}

<u>2- Cancel out the negative sign (common factor) from the numerator and denominator. This will give us:</u>
\frac{(85n^2+27n-76)}{(17n+19)}

<u>3- Factor the numerator. This wil give:</u>
\frac{(5n-4)(17n+19)}{(17n+19)}

<u>4- Finally, cancel out the (17n+19) which common in both numerator and denominator. This will give us the final expression:</u>
5n-4

Hope this helps :)
6 0
3 years ago
There are seven cats in my neighborhood, with an average of $41$ whiskers each. If one of the cats has $17$ whiskers, how many w
harkovskaia [24]

Answer:

Each of the other cats have 45 whiskers on average.

Step-by-step explanation:

Let x represent the average number of whisker of each cat.

We have been given that there are 7 cats in my neighborhood, with an average of 41 whiskers each.

The total number of whiskers of six cats would be 6x.

Since one of the cats has 17 whiskers, so the total number of whiskers of 7 cats would be 6x+17

We will use average formula to solve our given problem.

\text{Average}=\frac{\text{Sum of data points}}{\text{Number of data points}}

Upon substituting our given values, we will get:

41=\frac{6x+17}{7}

Let us solve for x.

41*7=\frac{6x+17}{7}*7

287=6x+17

287-17=6x+17-17

270=6x

Switch sides:

6x=270

\frac{6x}{6}=\frac{270}{6}

x=45

Therefore, the each of the other cats have 45 whiskers on average.

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Answer: i dont know trie asking linder0917

Step-by-step explanation:

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3 years ago
S=<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bn%7D%7B2%7D%20" id="TexFormula1" title=" \frac{n}{2} " alt=" \frac{n}{2} "
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