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ICE Princess25 [194]
3 years ago
12

If you roll a single die and count the number of dots on top, what is the sample space of all possible outcomes? Are the outcome

s equally likely?
Mathematics
1 answer:
azamat3 years ago
5 0

Answer:

Outcomes: S = {1, 2, 3, 4, 5, or 6}

The outcomes of rolling a single die are equally likely.

Step-by-step explanation:

A single fair die has six faces. Each face has dots on it, numbered {1, 2, 3, 4, 5, or 6}.

On rolling the die the possible outcomes are:

S = {1, 2, 3, 4, 5, or 6}

Thus, there are a total of 6 possible outcomes.

Equally likely events are events that has the same probability of happening.

For example, if events <em>A</em> and <em>B</em> are equally likely then <em>P </em>(<em>A</em>) = <em>P </em>(<em>B</em>).

The outcomes of rolling a die are equally likely because the probability of any of the 6 faces showing up are same, i.e.  

P(1) = P(2)=P(3)=P(4)=P(5)=P(6)=\frac{Favorable\ outcome}{Total\ no.\ of\ outcomes}=\frac{1}{6}

Thus, the outcomes of rolling a single die are equally likely.

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-4.6+5.3 help please thank you are the best
fomenos

Answer:

0.7

Step-by-step explanation:

6 0
2 years ago
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Complete parts a through c for the given function.
victus00 [196]

Answer:

a. The critcal points are at

x=0,-5,3

b. Then, x = -5   is a maximum and x=3 is a minimum

c. The absolute minimum is at   x = 3  and the absolute maximum is at  x = -5.

Step-by-step explanation:

(a)

Remember that you need to find the points where

f'(x)=0

Therefore you have to solve this equation.

20x^4  + 40x^3 - 300x^2 = 0

From that equation you can factor out    20x^2  and you would get

20x^2 (  x^2  +2x - 15)  = 0

And from that you would have   20x^2 = 0  , so x = 0.

And you would also have  x^2 +2x-15 = 0.

You can factor that equation as    x^2 +2x -15 = (x+5)(x-3) = 0

Therefore   x=-5 ,   x=3.

So the critcal points are at

x=0,-5,3

b.  

Remember that a function has a maximum at a critical point if the second derivative at that point is negative. Since

f''(x) = 80x^3 + 120x^2 -600x\\f''(-5) = 80(-5)^3 + 120(-5)^2 -600(-5) = -4000 < 0\\\\f''(3) = 80(3)^3 + 120(3)^2 -600(3) = 1440 > 0 \\

Then, x = -5   is a maximum and x=3 is a minimum

c.

The absolute minimum is at   x = 3  and the absolute maximum is at  x = -5.

6 0
3 years ago
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How do you solve this?
zaharov [31]
Angle 2 and angle 4 are vertical angles which makes them congruent
8 0
2 years ago
[(7+3)x5-4](divided by) 2+3<br> SHOW ALL WORK WILL MARK BRAINLIEST
Nesterboy [21]

Answer:

26

Step-by-step explanation:

[(7+3)5-4]/2+3

-To solve this equation you have to use PEMDAS

P- Parentheses

E- Exponents

M- Multiplication

D- Division

A- Addition

S- Subtraction-

- With MD and AS you work left to right of the equation since they are in the same spot. (PE[MD][AS])

Step 1) [(10)5-4]/2+3

- First you do "P," parentheses, so you add 7+3=10

Step 2) [50-4]/2+3

- Next you do "M," multiplication, and multiply 10x5=50

Step 3) [46]/2+3

- Then you do "S," subtraction, and subtract 50-4=46

(FYI: Steps 1-3 were still in the parentheses. We had to start with the parentheses in the parentheses, work PEMDAS, and now we are out of the parentheses and have to work PEMDAS on the rest of the problem.)

Step 4) 23+3

- Now we do "D," division, and divide 46/2=23

Step 5) 23+3=6

- Finally we do "A," addition, and add 23+3=26 so the answer is 26

(FYI: "/" means division)

4 0
2 years ago
Find the inverse y=3x+2
Gwar [14]

y=3x+2\\\\\text{replace x with y and y with x}\\\\3y+2=x\\\\\text{solve for y}\\\\3y+2=x\ \ \ \ \ |-2\\\\3y=x-2\ \ \ \ \ |:3\\\\\boxed{y=\dfrac{x-2}{3}}

4 0
3 years ago
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