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3 years ago

Another One I need help withhhh sorrry

Mathematics

1 answer:

Effectus [21]3 years ago

6 0

Answer:

y = 2x+3

Step-by-step explanation:

Sorry I'm probably too late since Quizziz doesn't wait unless you have the freeze timer thing.

y = mx+b

b is the y intercept. The y intercept (when x=0) is given in the table.

Now plug a coordinate in to solve for m.

My coordinates: (1,5)

5 = m + 3

Solve.

2 = m

m = 2

Note: never plug in the y intercept when looking for m.

You can also find the slope by (subtracting the y value of one coordinate from another y value of another coordinate)/(subtracting x value from the first y coordinate above from the x value from the second coordinate).

In this case, it'd be

m = (7-5)/(2-1)

m = 2/1

m = 2

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. A right cylindrical drum is to hold 7.35 cubic feet of liquid. Find the dimensions (radius of the base and height) of the drum

Drupady [299]

Answer:

$r=1.05\ \text{ft}$

$h=2.12\ \text{ft}$

$20.91\ \text{ft}^3$

Step-by-step explanation:

r = Radius

h = Height

Volume of cylinder = $7.35\ \text{ft}^3$

$V=\pi r^2h\\\Rightarrow h=\dfrac{V}{\pi r^2}\\\Rightarrow h=\dfrac{7.35}{\pi r^2}$

Surface area is given by

$A=2\pi r^2+2\pi rh\\\Rightarrow A=2\pi r^2+2\pi r\dfrac{7.35}{\pi r^2}\\\Rightarrow A=2\pi r^2+\dfrac{14.7}{r}$

Differentiating with respect to radius we get

$\dfrac{dA}{dr}=4\pi r-\dfrac{14.7}{r^2}$

Equating with zero we get

$0=4\pi r-\dfrac{14.7}{r^2}\\\Rightarrow 4\pi r=\dfrac{14.7}{r^2}\\\Rightarrow r^3=\dfrac{14.7}{4\pi}\\\Rightarrow r=(\dfrac{14.7}{4\pi})^{\dfrac{1}{3}}\\\Rightarrow r=1.05$

$\dfrac{d^2A}{dr^2}=4\pi-2\times \dfrac{14.7}{r^3}\\\Rightarrow \dfrac{d^2A}{dr^2}=4\pi+2\times \dfrac{14.7}{1.05^3}\\\Rightarrow \dfrac{d^2A}{dr^2}=37.96>0$

So, the value of the function is minimum at $r=1.05$

$h=\dfrac{7.35}{\pi r^2}=\dfrac{7.35}{\pi 1.05^2}\\\Rightarrow h=2.12$

So, the radius and height which would minimize the surface area is 1.05 feet and 2.12 feet respectively.

Surface area

$A=2\pi r^2+2\pi rh\\\Rightarrow A=2\pi \times 1.05^2+2\pi 1.05\times 2.12\\\Rightarrow A=20.91\ \text{ft}^3$

The minimum surface area is $20.91\ \text{ft}^3$ .

8 0

3 years ago

The diameter of Joe's large pizza is 19 inches. Approximately how many inches are there in the circumference of the large pizza?

Burka [1]

Answer:

There are 59.66 inches in the circumference of the large pizza.

Step-by-step explanation:

It is given that:

Diameter of Joe's large pizza = 19 inches

Diameter = 2r

2r = 19

Circumference of large pizza = 2πr = 2r * π

Circumference of large pizza = 19*3.14

Circumference = 59.66 inches

Therefore,

There are 59.66 inches in the circumference of the large pizza.

6 0

3 years ago

LB. Johnson middle school

Wewaii [24]

Answer:

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5 0

4 years ago

Slove for v<br> 8(v-4)+7v=-2

Butoxors [25]

8(v−4)+7v=−2

(8)(v)+(8)(−4)+7v=−2

8v+−32+7v=−2

(8v+7v)+(−32)=−2

15v+−32=−2

15v−32=−2

Add 32 to both sides.

15v−32+32=−2+32

15v=30

Divide both sides by 15.

15v/15=30/15

v = 2

6 0

3 years ago

Read 2 more answers

What is the perimeter of a rectangle with side lengths 6x-86x−8 and 3+14x3+14x

Ivahew [28]

EXPLANATION: (2x6)-10)+2(4x13+(12-20)

ANSWER: (20x14)=280 thats what i got lmk if its incorrect

5 0

2 years ago