The final answer is 10a+7
I leaerned this neat trick
you don't need to convert to vertex form
where
y=ax^2+bx+c
the x value of the vertex is -b/2a
the y value is found by inserting the x value of the vertex into the equation
so
1x^2-6x+14
-b/2a=-(-6)/2(1)=6/2=3
plug that in
y=x^2-6x+14
y=3^2-6(3)+14
y=9-18+14
y=5
the vertex is (3,5)
Answer:
(2A/h) - b1 = b2
Step-by-step explanation:
A = 1/2h (b1 + b2)
1. Multiply by 2 on both sides
2A = h (b1 + b2)
2. Divide by h on both sides
2A/h = b1 + b2
3. Subtract b1 on both sides
(2A/h) - b1 = b2
DONE
