3 years ago

I just have a couple more please help me

Mathematics

1 answer:

geniusboy [140]3 years ago

5 0

D should work your answer

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Find the slope of the line throgh each pair of points

svlad2 [7]

Answer:

19/24

Step-by-step explanation:

slope = rise/run = (y1 - y2) / (x1 - x2)

s = (19 - 0) / (8 - -16)

s = 19/24

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3 years ago

What is the slope of the function?

d1i1m1o1n [39]

Answer: -6

Step-by-step explanation:

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3 years ago

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Triangle PQR has the coordinates P(2,4), Q(-2,4), R(0,-5).

tensa zangetsu [6.8K]

Answer:

I hope I got this correct.

Step-by-step explanation:

Multiply the coordinates by 2.

P(4,8)

Q(-4,8)

R(0,-10)

For the future if you get stuck, multiply the coordinates by the dilation number.

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2 years ago

Find the 107 term of the sequence -9, -5, -1, 3, 7, ....

Alex17521 [72]

the sequence is 4n-13, so substitute 107 into n and it will become 4(107)-13 =415

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3 years ago

What is the product?( square root 3x+ square root 5) (square root 15x+ 2 square root 30)

hichkok12 [17]

$(\sqrt{3x}+\sqrt5)\cdot(\sqrt{15x}+2\sqrt{30})\\\\=(\sqrt{3x})(\sqrt{15x})+(\sqrt{3x})(2\sqrt{30})+(\sqrt5)(\sqrt{15x})+(\sqrt5)(2\sqrt{30})\\\\=\sqrt{(3x)(15x)}+2\sqrt{(3x)(30)}+\sqrt{(5)(15x)}+2\sqrt{(5)(30)}\\\\=\sqrt{45x^2}+2\sqrt{90x}+\sqrt{75x}+2\sqrt{150}\\\\=\sqrt{9x^2\cdot5}+2\sqrt{9\cdot10x}+\sqrt{25\cdot3x}+2\sqrt{25\cdot6}\\\\=\sqrt{9x^2}\cdot\sqrt5+2\sqrt9\cdot\sqrt{10x}+\sqrt{25}\cdot\sqrt{3x}+2\sqrt{25}\cdot\sqrt6$
$=3x\sqrt5+2\cdot3\sqrt{10x}+5\sqrt{3x}+2\cdot5\sqrt6\\\\=3x\sqrt5+6\sqrt{10}+5\sqrt{3x}+10\sqrt6$

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3 years ago

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