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Reika [66]
2 years ago
7

Look at bth plz help tysm

Mathematics
2 answers:
makvit [3.9K]2 years ago
8 0
C
Not sure tho i ain’t even look at the problem
tangare [24]2 years ago
4 0

Answer:

d

Step-by-step explanation:

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Please help!!-- What is the measure of arc AT in the circle O below?
Gala2k [10]

Answer:

97

Step-by-step explanation:

Arc AT = angle at the center 97°

4 0
3 years ago
Simplify <br>7b-2b+3b+4b
kolezko [41]
It should be just 12b, since they all have the same exponent, they can all be combined.
4 0
3 years ago
Read 2 more answers
A standard deck of cards contains 52 cards. One card is selected from the deck.​(a)Compute the probability of randomly selecting
Aneli [31]

a. There are four 5s that can be drawn, and \binom43=4 ways of drawing any three of them. There are \binom{52}3=22,100 ways of drawing any three cards from the deck. So the probability of drawing three 5s is

\dfrac{\binom43}{\binom{52}3}=\dfrac4{22,100}=\dfrac1{5525}\approx0.00018

In case you're asked about the probability of drawing a 3 or a 5 (and NOT three 5s), then there are 8 possible cards (four each of 3 and 5) that interest you, with a probability of \frac8{52}=\frac2{13}\approx0.15 of getting drawn.

b. Similar to the second case considered in part (a), there are now 12 cards of interest with a probability \frac{12}{52}=\frac3{13}\approx0.23 of being drawn.

c. There are four 6s in the deck, and thirteen diamonds, one of which is a 6. That makes 4 + 13 - 1 = 16 cards of interest (subtract 1 because the 6 of diamonds is being double counted by the 4 and 13), hence a probability of \frac{16}{52}=\frac4{13}\approx0.31.

- - -

Note: \binom nk is the binomial coefficient,

\dbinom nk=\dfrac{n!}{k!(n-k)!}={}_nC_k=C(n,k)=n\text{ choose }k

6 0
3 years ago
Determine the value of y when x=15 if y=6 when x =30
Vladimir79 [104]
6+9=15
y+9=x
x=30
y+9=30
y=21
6 0
3 years ago
Select the equation that contains the point (3, -9), and in which the graph of the line has a positive slope.
Kamila [148]
First thing to do is to solve each of these for y.  The first one is y=-4x-3; the second one is y=4x-21; the third one is y=4x+21; the fourth one is y=-4x+3.  From that you can tell the positive slopes are found in the second and third equations.  Those are the ones we will test now for the point (3, -9).  y=-9 and x=3, so let's fill in accordingly.  The second equation filled in is -9=4(3)-21.  Does the left side equal the right when we do the math?  -9=12-21 and -9=-9.  So the second one works.  Just for the sake of completion, let's do the same with the third: -9=4(3)+21.  Does -9=12+21?  Of course it doesn't.  Our equation is the second one above, y+9=4(x-3).
7 0
3 years ago
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