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Olegator [25]
3 years ago
5

A square rotated about its center by 360º maps onto itself at _____ different angles of rotation. You can reflect a square onto

itself across _____ different lines of reflection.
first blank: 1,2,3,4
last blank: 2,4,8,16
Mathematics
1 answer:
Lilit [14]3 years ago
5 0
Answer for the first blank: 4
Answer for the second blank: 4

-----------------------------------------------

A square has 4 angles of rotation. This means you can rotate a square 4 times to have it line up with its original image before you hit 360 degrees. 

A square has 4 lines of symmetry. They lines are the vertical and horizontal lines through the center. Also there are 2 diagonal lines of symmetry through the center. This makes 4 lines total.
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Rebecca must complete 15 hours of volunteer work. She does 3 hours each day. Write a linear equation in slope-intercept form to
ValentinkaMS [17]

Answer:

y = 15 hour - 3 hours/day x days

y = 15 - 3x

y-intercept = 15 - 3(0)= 15 which is the amount of volunteer hours she must complete at day 0.

0 = 15 - 3x

3x = 15

x = 5 (Number of days she would have to volunteer)

Equation: y = 15- 3x

Step-by-step explanation:

4 0
3 years ago
Select the expression that is equivalent to |4-3|
alexdok [17]

Answer:

5

Your're welcome!

3 0
3 years ago
Consider the quadratic equation x2 = 4x - 5. How many solutions does the equation have?
JulijaS [17]

Answer:

  • no real solutions
  • 2 complex solutions

Step-by-step explanation:

The equation can be rearranged to vertex form:

  x^2 -4x = -5 . . . . . . . . . subtract 4x

  x^2 -4x +4 = -5 +4 . . . . add 4

  (x -2)^2 = -1 . . . . . . . . . show the left side as a square

  x -2 = ±√-1 = ±i . . . . . . take the square root; the right side is imaginary

  x = 2 ± i . . . . . . . . . . . . . add 2. These are the complex solutions.

_____

<em>Comment on the question</em>

Every 2nd degree polynomial equation has two solutions. They may be real, complex, or (real and) identical. That is, there may be 0, 1, or 2 real solutions. This equation has 0 real solutions, because they are both complex.

3 0
3 years ago
-6x-5y=-6<br>3x+6y=24<br>solve for x and y​
zhannawk [14.2K]

Answer:

x= -4 and y=6

Step-by-step explanation:

-6x-5y=-6     -equation 1

3x+6y=24       -equation 2

Solving the equation 1 to get the value of

To solve such type of equations that have two unknown variables, find the value of one variable in terms of the other from any one of the equation and put the value in the second equation which will give the value of both the variables

Solving Equation 2 to find x

3x+6y=24

3x=24-6y

x=(24-6y)/3     =8-2y              equation 3

Putting this value of x in the equation 1

-6x-5y= -6

-6(8-2y)-5y= -6

-48+12y-5y= -6

7y= -6+48

7y= 42

y= 42/7 = 6, y=6

Putting the value of y in equation 3 to find the value of x

x=8-2y= 8-2(6)

x= -4

     

8 0
4 years ago
Find the value of 2a² + 5b² when a= -6 and b= 2
sashaice [31]
2(-6^2)+5(2^2)
2(36)+5(4)
72+20
92
4 0
3 years ago
Read 2 more answers
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