Answer:
Step-by-step explanation:
x² + x - 2 = x² - x +2x -2 = x(x - 1) + 2*(x-1) = (x-1)(x+2)
8x² + 4x = 4x ( 2x + 1)
3x² + 10x + 8 = 3x² + 6x + 4x + 4*2 =3x * (x + 2) + 4 * ( x + 2) = (x + 2)(3x + 4)
Answer:
Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line
is
Step-by-step explanation:
Given:
To Find:
Equation of line passing through ( 16, -7) and is perpendicular to the line
Solution:
...........Given

Comparing with,
Where m =slope
We get
We know that for Perpendicular lines have product slopes = -1.

Substituting m1 we get m2 as

Therefore the slope of the required line passing through (16 , -7) will have the slope,
Now the equation of line in slope point form given by
Substituting the point (16 , -7) and slope m2 we will get the required equation of the line,
Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line
is
49-28=21
51-32=19
23x7=161
14x5=70
Answer:
here are two possible solutions
Step-by-step explanation:
Answer:
x= 6, -4
Step-by-step explanation:
x^2 - 2x - 24 = 0
(x-6) (x+4) = 0
x = 6, x= -4