Problem 1
<h3>Answer: 7.3</h3>
Explanation: Apply the square root to the area to get the side length. This only applies to areas that are squares (hence the name).
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Problem 2
<h3>Answer: C) 1.3</h3>
Explanation: Use your calculator to find that choices A,B,D plugged into the square root function yield terminating decimal values. "Terminating" means "stop". This implies that they are perfect squares (though not perfect squares in the sense of whole number perfect squares which you may be used to). Choice C is the only value that has a square root that leads to a non-terminating decimal. The digits of this decimal go on forever without any pattern. The value is irrational.
- sqrt(5.29) = 2.3 terminating decimal
- sqrt(13.69) = 3.7 terminating decimal
- sqrt(1.3) = 1.140175425 keeps going forever without any pattern
- sqrt(0.09) = 0.3 terminating decimal
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Problem 3
<h3>Answer: 23.6 feet approximately</h3>
Explanation: Apply the square root to 15.5 to get roughly 3.937; this is the approximate side length of one square. Six of these tiles placed together will lead to a total length of roughly 6*3.937 = 23.622 which rounds to 23.6 feet. Like with problem 1, the square root being used like this only works for square areas.
Answer:
???
Step-by-step explanation:
Could I have the L&W please?
Answer:
a = 1, b = 1
Step-by-step explanation:
Expand the right side and compare the coefficients of like terms on both sides, that is
right side
(x - a)² + b ← expand factor using FOIL
= x² - 2ax + a² + b
Compare to left side x² - 2x + 2
Compare the coefficients of the x- term
- 2a = - 2 ( divide both sides by - 2 )
a = 1
Compare the constant terms
a² + b = 2 ( substitute a = 1 )
1² + b = 2
1 + b = 2 ( subtract 1 from both sides )
b = 1
Thus a = 1, b = 1
the rate given is 345 ft/min
this means within 1 min distance is - 345 ft
we have to convert this speed to ft/h
1 hour is equivalent to 60 minutes
so if 60 minutes equals 1 hour
1 minute is equal to - 1/60 hr
so the distance within 1 minute is - 345 ft
since 1 min = 1/60 hr
distance within 1/60 hour = 345 ft
therefore distance in 1 hour = 
answer is 20 700 ft/h
1. 10 or 10 to the first power
2. 10000 or 10 to the fourth power
3. 100 or 10 to the second power
4. 1000 or 10 to the third power
