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Sloan [31]
3 years ago
8

Which angle is an x-intercept for the function y = cos(1) A.0 B.2 C. £ D. 2£

Mathematics
1 answer:
noname [10]3 years ago
3 0

Answer: C. \pi

=======================================================

Explanation:

The x intercept always occurs when y = 0.

Use the unit circle to determine that \cos(\theta) = 0 when \theta = \frac{\pi}{2} \text{ and } \theta = \frac{3\pi}{2}

So if x = \pi, then we have

y = \cos\left(\frac{1}{2}x\right)\\\\y = \cos\left(\frac{x}{2}\right)\\\\y = \cos\left(\frac{\pi}{2}\right)\\\\y = 0\\\\

which shows us that (\pi, 0) is the location of one of the infinitely many x intercepts for this function.

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ASAP: I need as soon as possible with this question I have taken a picture of. If you could tell me how to do it and the answer,
VladimirAG [237]

Answer:

The answer to your question is h = 125.85 ft = 126 ft

Step-by-step explanation:

Process

1.- Determine two equations to solve the problem

    tan 14 = \frac{h}{x}                     (1)

    tan 47 = \frac{h}{x - 386}           (2)

    from (1)                           h = xtan14

    substitute in (2)             tan 47 = \frac{xtan14}{x - 386}

    solve for x                     tan47(x - 386) = xtan14

                                          1.07x - 413.9 = 0.25x

                                          1.07x - 0.25x = 413.9

                                           0.82x = 413.9

                                           x = 413.9/0.82

                                           x = 504.76 ft

2.- Calculate h

                                          h = 504.76 tan 14

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4 0
3 years ago
Given triangle abc with vertices A(2,-1), B(5,6), C(-1,4) as shown. Find the number of square units in the area of triangle abs
Roman55 [17]

Answer:

The area of the triangle is 18 square units.

Step-by-step explanation:

First, we determine the lengths of segments AB, BC and AC by Pythagorean Theorem:

AB

AB = \sqrt{(5-2)^{2}+[6-(-1)]^{2}}

AB \approx 7.616

BC

BC = \sqrt{(-1-5)^{2}+(4-6)^{2}}

BC \approx 6.325

AC

AC = \sqrt{(-1-2)^{2}+[4-(-1)]^{2}}

AC \approx 5.831

Now we determine the area of the triangle by Heron's formula:

A = \sqrt{s\cdot (s-AB)\cdot (s-BC)\cdot (s-AC)} (1)

s = \frac{AB+BC + AC}{2} (2)

Where:

A - Area of the triangle.

s - Semiparameter.

If we know that AB \approx 7.616, BC \approx 6.325 and AC \approx 5.831, then the area of the triangle is:

s \approx 9.886

A = 18

The area of the triangle is 18 square units.

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3 years ago
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Answer:

Step-by-step explanation:

8 0
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14. The cost of 10 dozen of caps is Rs.800. How many caps can bebought for Rs.200.​
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Answer:

Step-by-step explanation:

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Do 1,500x0.55 which equals
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