Answer:
- second kick goes farther
- first kick goes higher
Step-by-step explanation:
Assuming the kick started from ground level, the path of the ball is assumed to be symmetrical about the high point. That is, the first kick will land 2×20 = 40 yards downfield.
The equation for the second kick can be rewritten as ...
y = 0.008x(50 -x)
The value of y will be zero at x=0 and at x=50. The second kick will land 50 yards downfield, a greater distance than the first kick.
At x=25, the height of the second kick is ...
y = 0.008(25)(50-25) = 5 . . . yards
The second kick travels farther (50 yds vs. 40 yds).
The first kick travels higher (8 yds vs. 5 yds).
