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Sav [38]
3 years ago
5

Para alavancar seus lucros, o dono de uma empresa passou a investir mais no meio digital, começando pelo seu site. Com base em u

ma análise de 6 meses, percebeu que, para cada x reais investidos dentro de um mês, a quantidade y de visualizações de seu site obedecia à função F(x)=40x+80 o valor que ele deverá investir, no próximo mês, para que o seu site alcance 35 000 visualizações é?
Mathematics
1 answer:
ella [17]3 years ago
8 0

Answer:

85.5 reals

Step-by-step explanation:

Aqui, usando a função de análise, queremos saber a quantidade de dinheiro que deve ser investido para fornecer o número de visualizações.

A maneira como podemos resolver isso é através da substituição. Precisamos apenas substituir F (x) na equação e resolver x, o que nos dará a idéia da quantidade de dinheiro a ser investido.

matematicamente

F (x) = 40x + 80

3500 = 40x + 80

40x = 3500-80 40x = 3420 x = 3420/40

x = 85,5 reais

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Can someone please help me with my maths question​
DIA [1.3K]

Answer:

a. \  \dfrac{625 \cdot m}{27 \cdot n^{11}}

b. \  \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}

Step-by-step explanation:

The question relates with rules of indices

(a) The give expression is presented as follows;

\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}

By expanding the expression, we get;

\dfrac{m^3 \times n^{-8} \times 5^4 \times m^4}{\left 3^3 \times m^6 \times n^3}

Collecting like terms gives;

\dfrac{m^{(3 + 4 - 6)}  \times 5^4}{ 3^3 \times n^{3 + 8}} = \dfrac{625 \cdot m}{27 \cdot n^{11}}

\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}= \dfrac{625 \cdot m}{27 \cdot n^{11}}

(b) The given expression is presented as follows;

x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \div (x \cdot y^n)^4

Therefore, we get;

x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times  x^{-4} \times y^{-4 \cdot n}

Collecting like terms gives;

x^{3 \cdot m + 2 - 4} \times \left (y^{3 \cdot n - 3 -4 \cdot n}} \right ) = x^{3 \cdot m - 2} \times \left (y^{ - 3 -n}} \right ) = x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right )

x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right ) = \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}

x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times  x^{-4} \times y^{-4 \cdot n} =\dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}

4 0
3 years ago
What is the slope of a line that is parallel to the line y 3/4x+2
Ronch [10]

Answer:

-4/3

Step-by-step explanation:

mtan × mline = -1

mtan× 3/4 = -1

mtan =-4/3

7 0
2 years ago
Sara spent half of her allowance going to the movies. She washed the family car and earned 9 dollars. What is her weekly allowan
Genrish500 [490]
$7, I think. I would not be too sure about it, though.
3 0
3 years ago
Read 2 more answers
. The new saleswoman at Clocks Unlimited was very good. During her first day on the job she sold at least two of each of the thr
LiRa [457]

Answer:

5

Step-by-step explanation:

Let the number of the kitchen clock sold =a

Let the number of the cuckoo clock sold =b

Let the number of the two-foot high grandfather clocks sold =c

The new saleswoman sold at least two of each of the three models.

Therefore:

a\geq 2\\b \geq 2\\c \geq 2

In all, she collected $300 from selling these models alone

17a+31b+61c=300

17(2)+31(2)+61(2)=218

300-218=82

Next, we try to express the remainder (82) in terms of 17, 31 and 61

82=17(3)+31

Therefore, she sold:

  • 5 kitchen clocks
  • 3 cuckoo clocks
  • 2 two-foot high grandfather clocks

She sold 5 $17 clocks.

CHECK:

17(5)+31(3)+2(61)=$300

4 0
3 years ago
Please help me with this question! i will give brainiest if correct! (if you show me how to lol i have no idea how)
Nitella [24]

Answer:

  • y(2x² + y) / x(5y² - 6x)

Step-by-step explanation:

<u>Simplify the numerator:</u>

  • 1/x² + 2/y =
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  • (2x² + y)/(x²y)

<u>Simplify the denominator:</u>

  • 5/x - 6/y² =
  • 5y²/(xy²) - 6x/(xy²) =
  • (5y² - 6x) / (xy²)

<u>Simplify the fraction:</u>

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  • y(2x² + y) / x(5y² - 6x)
7 0
3 years ago
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