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ad-work [718]
4 years ago
13

An object with a mass of 3.0kg has a force of 9.0 newtons applied to it. What is the resulting acceleration of

Physics
1 answer:
Sindrei [870]4 years ago
3 0

Answer:

The acceleration is: a=3 \frac{m}{s^2}

Explanation:

To answer this, we need to recall Newton's Second Law of motion, that states that an object of mass m would accelerate (change its state of uniform motion) proportional to the force (F) that is applied , and exemplified by the following equation:

F=m\,a

From here, and using the given values for mass (m = 3 kg) and force (F = 9 N), we can derive the value of the acceleration as shown below (notice that since all quantities are given in SI units, the resulting acceleration will also be in Si units (\frac{m}{s^2}):

F=m\,a\\9\,N=3\,kg\,a\\a=\frac{9}{3} \frac{m}{s^2} \\a=3 \frac{m}{s^2}

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shepuryov [24]

Answer:

v=\sqrt{\frac{kZe^2}{mr}}

Explanation:

The electrostatic attraction between the nucleus and the electron is given by:

F=k\frac{(e)(Ze)}{r^2}=k\frac{Ze^2}{r^2} (1)

where

k is the Coulomb's constant

Ze is the charge of the nucleus

e is the charge of the electron

r is the distance between the electron and the nucleus

This electrostatic attraction provides the centripetal force that keeps the electron in circular motion, which is given by:

F=m\frac{v^2}{r} (2)

where

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Combining the two equations (1) and (2), we find

k\frac{Ze^2}{r^2}=m\frac{v^2}{r}

And solving for v, we find an expression for the speed of the electron:

v=\sqrt{\frac{kZe^2}{mr}}

6 0
3 years ago
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riadik2000 [5.3K]

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Explanation:

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