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Murljashka [212]
3 years ago
8

At one time, it was thought that positive charge was spread throughout the atom. This was the plum-pudding model. Rutherford's e

xperiment to test this theory involved shooting positively charged particles toward the atom. Describe what the results of this experiment would have been if the plum-pudding model were correct.
Physics
2 answers:
laiz [17]3 years ago
7 0
The 2 positively charged particles would repel each other.
dezoksy [38]3 years ago
4 0

Answer:

1) All the alpha particles must have deviated at some angle from their initial path.

2) None of the alpha particle will go out undeviating

Explanation:

In Rutherford's experiment he bombarded alpha particles on the nucleus of gold atom and then he observed that most of the alpha particles moves out undeviating while few of them shows small deflection.

But the most shocking part of experiment was that he saw that one out of 10,000 alpha particles are such which retrace their initial path i.e. those alpha particles are deviated nearly 180 degree angle.

Now these all observations will concluded as

1. Most of the part of atom is vacant and hence atom is not made up of positively charged.

2. Electrons revolves around the nucleus in circular orbits

3. The positive charge of the nucleus is concentrated at the nucleus of of atom which is a very small and dense volume of atom.

So these results are totally opposite of plum pudding model because as per plum pudding model the atom is a positively charged sphere and electrons are randomly placed in it.

If this model is assumed to be correct then in that case the observations must be like following

1) All the alpha particles must have deviated at some angle from their initial path.

2) None of the alpha particle will go out undeviating

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Answer:

A hypothesis is a conjecture, based on knowledge obtained while seeking answers to the question. The hypothesis might be very specific, or it might be broad. Scientists then test hypotheses by conducting experiments or studies.

Explanation:

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Your answer is c. homologous structures
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Two children are balanced on a seesaw that has a mass of 18.0 kg. The first child has a mass of 26.0 kg and sits 1.60 m from the
Mashcka [7]

Answer:

1.28 m

Explanation:

As shown in the diagram attached,

According to the principle of moment,

For a body at equilibrium,

Sum of clockwise moment = sum of anticlockwise moment.

Taking moment about the pivot,

W₁(1.6)+W(0.133) = W₂(x)............... Equation 1

Where W₁ = Weight of the first child, Wₓ = Weight of the seesaw, W₂ = weight of the second child, x = distance of the second child from the pivot.

But,

W = mg

Where g = 9.8 m/s², m = mass of the body

Therefore,

W₁ = 26×9.8 = 254.8 N,

Wₓ = 18×9.8 = 176.4 N

W₂ = 34.4×9.8 = 337.12 N

Substitute these values into equation 1

(254.8×1.6)+(176.4×0.133) = 337.12(x)

407.68+23.4612 = 337.12x

337.12x = 431.1412

x = 431.1412/337.12

x = 1.2789

x ≈ 1.28 m

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