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Murljashka [212]
3 years ago
8

At one time, it was thought that positive charge was spread throughout the atom. This was the plum-pudding model. Rutherford's e

xperiment to test this theory involved shooting positively charged particles toward the atom. Describe what the results of this experiment would have been if the plum-pudding model were correct.
Physics
2 answers:
laiz [17]3 years ago
7 0
The 2 positively charged particles would repel each other.
dezoksy [38]3 years ago
4 0

Answer:

1) All the alpha particles must have deviated at some angle from their initial path.

2) None of the alpha particle will go out undeviating

Explanation:

In Rutherford's experiment he bombarded alpha particles on the nucleus of gold atom and then he observed that most of the alpha particles moves out undeviating while few of them shows small deflection.

But the most shocking part of experiment was that he saw that one out of 10,000 alpha particles are such which retrace their initial path i.e. those alpha particles are deviated nearly 180 degree angle.

Now these all observations will concluded as

1. Most of the part of atom is vacant and hence atom is not made up of positively charged.

2. Electrons revolves around the nucleus in circular orbits

3. The positive charge of the nucleus is concentrated at the nucleus of of atom which is a very small and dense volume of atom.

So these results are totally opposite of plum pudding model because as per plum pudding model the atom is a positively charged sphere and electrons are randomly placed in it.

If this model is assumed to be correct then in that case the observations must be like following

1) All the alpha particles must have deviated at some angle from their initial path.

2) None of the alpha particle will go out undeviating

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A 4.0 kg shot put is thrown with 30 N of force. What is its acceleration?
weeeeeb [17]

7.5 m/s

a = F ÷ m

a = (30 N) ÷ (4.0 kg)

a = 7.5 m/s2

7 0
3 years ago
what is the resistance of a car light bulb that conducts 0.025A current when connected to a 12V car accumulator? is the current
Sophie [7]

One form of Ohm's Law says . . . . . Resistance = Voltage / Current .

R = V / I

R = (12 v) / (0.025 A)

R = (12 / 0.025) (V/I)

<em>R = 480 Ohms</em>

I don't know if the current in the bulb is steady, because I don't know what a car's "accumulator" is.  (Floogle isn't sure either.)

If you're referring to the car's battery, then the current is quite steady, because the battery is a purely DC storage container.

If you're referring to the car's "alternator" ... the thing that generates electrical energy in a car to keep the battery charged ... then the current is pulsating DC, because that's the form of the alternator's output.  

7 0
3 years ago
When material allow to heat to pass though them rapidly they are known as __________​
Katarina [22]

Answer:

They are conductors/conductive. Materials that can transfer thermal energy well are conductive.

Explanation:

5 0
2 years ago
Read 2 more answers
If a ball that is 10 meters above the ground is thrown horizontally at 5.51 meters per second. a. how long will it take for the
GalinKa [24]

Answer:

a. t = 1.43 s

b. d = 7.88 m

Explanation:

a. The time of flight can be found using the following equation:

y_{f} = y_{0} + v_{0_{y}}t - \frac{1}{2}gt^{2}

Where:

y_{f}: is the final height = -10 m

y_{0}: is the initial height = 0

v_{0_{y}}: is the initial speed in the vertical direction = 0

g: is the acceleration due to gravity = 9.81 m/s²

By solving the above equation for "t" we have:

t = \sqrt{\frac{2y_{f}}{g}} = \sqrt{\frac{2*10 m}{9.81 m/s^{2}}} = 1.43 s

Hence, the ball will hit the ground in 1.43 s.

b. The distance in the horizontal direction can be found as follows:

x_{f} = x_{0} + v_{0}t + \frac{1}{2}at^{2}

Where:

x₀: is the initial position in the horizontal direction = 0

a: is the acceleration in the horizontal direction = 0 (it is moving at constant speed)

x_{f} = 5.51 m/s*1.43 s = 7.88 m

Therefore, the ball will travel 7.88 m before it hits the ground.

I hope it helps you!

4 0
2 years ago
Means/end analysis involves:_________
polet [3.4K]

a. a gradual approximation to the final solution

Explanation:

Means/end analysis is a process that involves creation of an end goal to enable the identified means to apply.

In this techniques sub-goals are formed to eliminate the challenges faced in application of a selected operator.

It starts by identifying a predetermined goal which is followed by actions that will led to the goal.

Learn More

Mean/end analysis : brainly.com/question/1213695

Keywords : mean, end, analysis

#LearnwithBrainly

4 0
3 years ago
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