U^16 is the answer to this problem
Answer:
We have to use the formule to calculate the vertex which is: V(-b/2a;4ac-b^2/4a)
A) y=x+7 where a=1 b=0 and c=7
By replacing we have: V(0;28/4) V(0;7)
B) y=-x where a=-1 b and c=0 so V(0,0)
Answer:
m∠PTQ = 40°
Step-by-step explanation:
From the picture attached,
Two lines PS and RQ are intersecting each other at a point T.
Vertical angles formed at the point of intersection T will be equal in measure.
m∠PTQ = m∠STR and m∠PTR = m∠QTS
Therefore, (x + 28)° = (2x + 16)°
28 - 16 = 2x - x
12 = x
m∠PTQ = (x + 28)°
= 12 + 28
= 40°
Therefore, measure of angle PTQ is 40°.
Answer:
27
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Step-by-step explanation:
<u>Step 1: Define</u>
3 - 6(z - 2)
z = -2
<u>Step 2: Evaluate</u>
- Substitute in <em>z</em>: 3 - 6(-2 - 2)
- (Parenthesis) Subtract: 3 - 6(-4)
- Multiply: 3 + 24
- Add: 27