Answer:
The angle is 
.
Step-by-step explanation:
The building is 35 feet tall, and the rope is 400 feet long.Applying the trigonometric function, we have;
Sin θ = 
The height of the building represents the opposite side, while the length of the rope represents the hypotenuse. Thus;
Sin θ = 
Sin θ = 0.0875
θ = 
0.0875
= 
The angle made by the rope with respect to the ground is approximately .
Mid term :
Q1 = (88 + 85)/2 = 86.5
Q2 = (92 + 95)/2 = 93.5
Q3 = 100
IQR = Q3 - Q1 = 100 - 86.5 = 13.5
final exams :
Q1 = (65 + 78)/2 = 71.5
Q2 = (88 + 82)/2 = 85
Q3 = (95 + 93)/2 = 94
IQR = Q3 - Q1 = 94 - 71.5 = 22.5
so the final exams has the largest IQR
Answer:
3/4
Step-by-step explanation:
To answer this question we must first calculate the area of GHJK:
- A= GH*HJ
- A= (LM/2)* (MN/2)
- A= LM*MN/4
- LM/MN is the area of LMNO
- So the area of LMNO is 4 times the area of GHJK
- A is the area of LMNO and S the area of GHJK
- S= A/4
- A-S= A-A/4 = 3A/4
- so the area that is not shaded is 3/4
Answer:
7g+5 I'm pretty sure
Step-by-step explanation:
6g+g=7g 9-4=5
so it's 7g+5 simplified
