I think it would be b) because you're given a slope of 0, so that leaves you with
, resulting into this
You'd be just left with a continuous horizontal line going through the y-axis of 3 since you're passing the point (2,3), where 3 represents the y-value when your slope is at 0.
So you need to turn 5x^2 -3x -9 into 2x - 3.
Well first you need to take 5x^2 out by subtracting 5x^2 (-5x^2).
Then -3x needs to become 2x by adding 5x (+5x).
Finally -9 needs to become -3 by adding 6 (+6).
Put all the things you did together to make a polynomial.
-5x^2 + 5x + 6
Answer:
Step-by-step explanation:
Let's start with the equation of the volume of a cylinder:
Where:
- r is the radius of the cylinder (r=D/2=24/2=12 cm)
- h is the high of the cylinder (h = 60 cm)
We can us partial derivatives to find the differential of this volume. So we will have:
(1)
Now:
dr is a differential of the radius, so in our case it is 0.1 cm and dh, differential of the high, is 0.1*2 cm. We multiply by 2 because we need to consider the top and the bottom of the cylinder.
Now we just need to put all of this definitions in the equation (1).
I hope it helps you!
